Rs Aggarwal 2017 Solutions for Class 8 Math Chapter 22 Constructing And Interpreting Bar Graphs are provided here with simple step-by-step explanations. These solutions for Constructing And Interpreting Bar Graphs are extremely popular among Class 8 students for Math Constructing And Interpreting Bar Graphs Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2017 Book of Class 8 Math Chapter 22 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2017 Solutions. All Rs Aggarwal 2017 Solutions for class Class 8 Math are prepared by experts and are 100% accurate.

Page No 242:

Question 1:

The marks of a student in different subjects are given below:

Subject English Hindi Mathematics Science Social science
Marks 72 63 80 56 65
Draw a bar graph from the above information.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the names of the subjects at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 1 mark
Step 4: Then the height of the various bars are:
            Hindi = 72
            English = 63
            Mathematics = 80
            Science = 56
            Social science = 65
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:

Page No 242:

Question 2:

The following table shows the yearwise strength of a school
 

Year 2010−11 2011−12 2012−13 2013−14 2014−15
No. of students 950 1125 1400 1750 1900

Represent the above data by a bar graph.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the time intervals in years at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 50 students
Step 4: Then the height of the various bars are:
         Number of students in the year 2010 - 11 = 150×950 = 19 small divisionsNumber of students in the year 2011 - 12 = 150×1125 = 22.5 small divisionsNumber of students in the year 2012 - 13 = 150×1400 = 28 small divisionsNumber of students in the year 2013 - 14 = 150×1750 = 35 small divisionsNumber of students in the year 2014 - 15 = 150×1900 = 38 small divisions
          
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:

Page No 242:

Question 3:

The following table shows the favourite sports of 300 students of a school.
 

Sports Cricket Badminton Football Tennis Swimming
No. of students 85 60 55 35 65

Represent the above data by a bar graph.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the names of the sports at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 1 students
Step 4: Then the height of the various bars are:
            Cricket = 85
            Football = 60
            Tennis =  55
            Badminton =  35
            Swimming = 65
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.
The completed bar graph is as shown below:

Page No 242:

Question 4:

The air distances of four cities from Delhi (in km) are given below:
 

City Mumbai Kolkata Hyderabad Chennai
Distance from Delhi(in km) 1100 1340 1220 1700
Draw a bar graph to represent the above data.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the time interval in years at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 10 km
Step 4: Then the height of the various bars are:
Distance of Mumbai from Delhi  = 110×1100 = 110 small divisionsDistance of Kolkata from Delhi  = 110×1340 = 134 small divisionsDistance of Hyderabad from Delhi  = 110×1220 = 122 small divisionsDistance of Chennai from Delhi  = 110×1700 = 170 small divisions
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:

Page No 242:

Question 5:

The following table shows the life expectancy (average age to which people live) in various
countries in a particular year.
 

Country India Japan Britain Ethiopia Cambodia
Lifeexpectancy (in years) 65 80 75 50 45

Represent the above data by a bar graph.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis respectively.
Step 2: Along OX, write the names of the countries at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 1 year
Step 4: Then the height of the various bars are:
            India        : 65
            Japan       : 80
            Britain     : 75
            Ethiopia   :  50
            Cambodia : 45
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.
The completed bar graph is as shown below:

Page No 242:

Question 6:

Various modes of transport used by 2150 students of a school are given below:
 

School bus Private bus Scooter Bicycle By foot
750 460 130 370 440

Draw a bar graph to represent the above data.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the names of the states of India at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 10 student
Step 4: Then the height of the various bars are:
Number of students who used School bus= 110×750 =75 small divisionsNumber of students who used Private bus= 110×460 =46 small divisionsNumber of students who used Scooter= 110×130 =13 small divisionsNumber of students who used Bicycle= 110×370 =37 small divisionsNumber of students who went on their foot= 110×440 =44 small divisions
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:

Page No 242:

Question 7:

The following table shows the number of motorcycles produced by a company during six
consecutive years.
 

2009 2010 2011 2012 2013 2014
14000 16000 18500 21000 24000 30000

Draw a bar graph to represent the above data

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the years of census at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 500 motorcycles
Step 4: Then the height of the various bars are:
Number of motorcycles in 2009= 1500×14000 = 28 small divisionsNumber of motorcycles in 2010= 1500×16000 = 32 small divisionsNumber of motorcycles in 2011= 1500×18500 = 37 small divisionsNumber of motorcycles in 2012= 1500×21000 = 42 small divisionsNumber of motorcycles in 2013= 1500×24000 = 48 small divisionsNumber of motorcycles in 2014= 1500×30000 = 60 small divisions
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:



Page No 243:

Question 8:

The present population (in lakhs) of six Indian states is given below:
 

State Population(in lakhs)
Bihar 1040
Chhattisgarh 260
Jharkhand 330
Madhya Pradesh 720
West Bengal 910
Rajasthan 690

Represent the above data by a bar graph.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the years at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 10 lakhs
Step 4: Then the height of the various bars are:
Population of Bihar=110×1040=104 small divisionsPopulation of Chhattisgarh=110×260=26 small divisionsPopulation of Jharkhand=110×330=33 small divisionsPopulation of Madhya Pradesh=110×720=72 small divisionsPopulation of West Bengal=110×910=91 small divisionsPopulation of Rajasthan=110×690=69 small divisions
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:

Page No 243:

Question 9:

There are 1120 creatures in a zoo as per list given below:
 

Beast animals Other land animals Water animals Birds Reptiles
220 410 165 190 135

Represent the above data by a bar graph.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the names of the places at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 10 animals
Step 4: Then the height of the various bars are:
Beast animals in zoo= 110×220=22 small divisionsOther land animals in zoo= 110×410=41 small divisionsWater animals in zoo= 110×165=16.5 small divisionsBirds in zoo= 110×190=19 small divisionsReptiles in zoo= 110×135=13.5 small divisions
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:

Page No 243:

Question 10:

The following table shows the export earnings of India (in thousand crore rupees) during five consecutive years.
 

Year 2010−11 2011−12 2012−13 2013−14 2014−15
Export(in thousand crores rupees) 540 600 750 950 110
Represent the above data by a bar graph.

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the names of the countries at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 10 thousand crore rupees.
Step 4: Then the height of the various bars are:
Export in 2010−11 : 54010=54 small divisions

Export in 2011−12 : 60010=60 small divisions
Export in 2012−13 : 75010=75 small divisions
Export in 2013−14 : 95010=95 small divisions
Export in 2013−15 : 110010=110 small divisions


Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.

The completed bar graph is as shown below:

Page No 243:

Question 11:

The following data shows India's total population (in millions) from 1961 to 201l.

 

Year 1961 1971 1981 1991 2001 2011
Population (in millions) 360 420 540 680 1020 1200

Represent the above data by a bar graph

Answer:

The following steps are followed while drawing the bar graph:

Step 1: On a graph paper, draw a horizontal line OX and a vertical line OY, representing the x-axis and y-axis, respectively.
Step 2: Along OX, write the names of the soap brands at points taken at uniform gaps.
Step 3: Choose the scale: 1 small division = 10 millions people
Step 4: Then the height of the various bars are:
Population in 1961 = 110×360=36 small divisions
Population in 1971 = 110×420=42 small divisions
Population in 1981 = 110×540=54 small divisions
Population in 1991 = 110×680=68 small divisions
Population in  2001= 110×1020=102 small divisions
Population in 2011 = 110×1200=120 small divisions
Step 5: On the x-axis, draw bars of equal width and of heights obtained in step 4 at the points marked in step 2.
The completed bar graph is as shown below:

Page No 243:

Question 12:

In a survey of 100 families of a village, the number of members in each family was recorded, as shown by the bar graph given below:



Read the bar graph carefully and answer the following questions.
(I) What does the bar graph show?
(il) How many families have less than fivemembers?
(Iii) How many families have more than three members?
(iv) How many families have two children?

Answer:

(i) The given bar graph shows the number of members in 100 families of a village.

(ii) Number of families having 2 members = 5
Number of families having 3 members = 30
Number of families having 4 members = 55
∴Total number of families haing less than five members = 5 + 30 + 55 = 90

(iii) Number of families having 4 members = 55
Number of families having 5 members = 10
∴Total number of families haing more than three members = 55 + 10 = 65
(iv) Number of families having 2 children = Number of families having 4 members = 55 = (60+35+75+50+60)5 = 2805= 56



Page No 244:

Question 13:

Look at the bar graph given below:




Read the above bar graph carefully and answer the questions given below.
(i) What does the bar graph show?
(tt) In which subject is the student very poor?
(Iii) If maximum marks in each subject be 100, what is the average of his marks?
(Iv) On the basis of marks obtained, fmd the subject in which the student has special interest.

Answer:

(i) The given bar graph shows the marks scored by a student in five different subjects in his exams.
(ii) It is clear from the graph that the bar of the minimum height corresponds to English. So, the student is poor in English.
(iii) Average marks scored by the student =55+80+30+60+455=2705=54
(iv) It is clear from the graph that the bar of the maximum height corresponds to Mmathematics. So, the student has special interest in mathematics.

Page No 244:

Question 14:

Given below is a bar graph showing the heights of five mountain peaks.


Read the bar graph carefully and answer the following questions.
(i) Name the highest peak and mention its height.
(ii) What is the ratio between the heights of the lowest and the highest peaks?
(iii) Arrange the heights of the given peaks in an ascending order.
(iv) Which peaks differ in height by 600 metres?

Answer:

(i) It is clear from the graph that the bar of the maximum height corresponds to Mount Everest. So, the highest peak is Mount Everest.
The height of Mount Everest is 8800 m.

(ii) It is clear from the graph that the bar of the maximum height corresponds to Mount Everest. So, the highest peak is Mount Everest.
The height of Mount Everest is 8800 m.
It is clear from the graph that the bar of the minimum height corresponds to Annapurna. So, the lowest peak is Annapurna.
The height of Annapurna is 6000 m.
Required ratio = 88006000=2215 or 22 : 15

(iii) The heights of the given peaks 8800 m, 6000 m, 7500 m, 8200 m and 8000 m.
The heights of the given peaks in an ascending order is given by
6000 m, 7500 m, 8000 m, 8200 m and 8800 m.

(iv)The height of Mount Everest is 8800 m.
The height of Kanchenjunga  is 8200 m.
The difference between the heights of these two peaks is 8800 − 8200 = 600 m.
The two peaks differ in height by 600 metres are Mount Everest and Kanchenjunga.



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