Rs Aggarwal 2018 Solutions for Class 8 Math Chapter 2 Exponents are provided here with simple step-by-step explanations. These solutions for Exponents are extremely popular among Class 8 students for Math Exponents Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2018 Book of Class 8 Math Chapter 2 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2018 Solutions. All Rs Aggarwal 2018 Solutions for class Class 8 Math are prepared by experts and are 100% accurate.
Page No 33:
Question 1:
Evaluate:
(i) 4−3
(ii)
(iii)
(iv)
(v)
Answer:
(i)
(ii)
(iii)
(iv)
(v)
Page No 33:
Question 2:
Evaluate:
(i)
(ii)
(iii)
(iv)
Answer:
(i)
(ii)
(iii)
(iv)
Page No 33:
Question 3:
Evaluate:
(i)
(ii)
(iii)
Answer:
(i)
(ii)
(iii)
Page No 33:
Question 4:
Evaluate:
(i)
(ii)
(iii)
Answer:
(i)
(ii)
(iii)
Page No 33:
Question 5:
Evaluate
Answer:
Page No 33:
Question 6:
Evaluate
Answer:
Page No 33:
Question 7:
Evaluate
Answer:
Page No 33:
Question 8:
Find the value of:
(i) (20 + 3−1) × 32
(ii) (2−1 × 3−1) ÷ 2−3
(iii)
Answer:
(i)
(ii)
(iii)
Page No 34:
Question 9:
Find the value of x for which
Answer:
Consider the left side:
Given:
Comparing the powers:
Page No 34:
Question 10:
Find the value of x for which
Answer:
Given:
Page No 34:
Question 11:
By what number should (−6)−1 be multiplied so that the product becomes 9−1?
Answer:
Let the required number be .
The greatest common divisor for the numerator and the denominator is 3.
Page No 34:
Question 12:
By what number should be divided so that the quotient may be ?
Answer:
Let the number be .
Page No 34:
Question 13:
If 52x + 1 ÷ 25 = 125, find the value of x.
Answer:
Given:
Page No 36:
Question 1:
Write each of the following numbers in standard form:
(i) 57.36
(ii) 3500000
(iii) 273000
(iv) 168000000
(v) 4630000000000
(vi) 345 × 105
Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Page No 36:
Question 2:
Write each of the following numbers in usual form:
(i) 3.74 × 105
(ii) 6.912 × 108
(iii) 4.1253 × 107
(iv) 2.5 × 104
(v) 5.17 × 106
(vi) 1.679 × 109
Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Page No 36:
Question 3:
(i) The height of Mount Everest is 8848 m. Write it in standard form.
(ii) The speed of light is 300000000 m/sec. Express it in standard form.
(iii) The distance from the earth to the sun is 149600000000 m. Write it in standard form.
Answer:
(i) The height of the Mount Everest is 8848 m.
In standard form, we have:
.
(ii) The speed of light is 300000000 m/s.
In standard form, we have:
(iii) The SunEarth distance is 149600000000 m.
In standard form, we have:
Page No 36:
Question 4:
Mass of earth is (5.97 × 1024) kg and mass of moon is (7.35 × 1022) kg. What is the total mass of the two?
Answer:
Mass of the Earth =
Now,
So, the mass of the Earth can also be written as .
Mass of the Moon =
Sum of the masses of the Earth and the Moon:
Page No 36:
Question 5:
Write each of the following numbers in standard form:
(i) 0.0006
(ii) 0.00000083
(iii) 0.0000000534
(iv) 0.0027
(v) 0.00000165
(vi) 0.00000000689
Answer:
(i)
(ii)
(iii)
(iv)
(v) 0.00000165 =
(vi) 0.00000000689 =
Page No 36:
Question 6:
(i) 1 micron = m. Express it in standard form.
(ii) Size of a bacteria = 0.0000004 m. Express it in standard form.
(iii) Thickness of a paper = 0.03 mm. Express it in standard form.
Answer:
(i)
(ii)
(iii)
Page No 36:
Question 7:
Write each of the following numbers in usual form:
(i) 2.06 × 10−5
(ii) 5 × 10−7
(iii) 6.82 × 10−6
(iv) 5.673 × 10−4
(v) 1.8 × 10−2
(vi) 4.129 × 10−3
Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Page No 37:
Question 1:
Tick (✓) the correct answer
The value of is
(a)
(b)
(c)
(d)
Answer:
(c)
Page No 37:
Question 2:
Tick (✓) the correct answer
The value of (−3)−4 is
(a) 12
(b) 81
(c)
(d)
Answer:
(d)
Page No 37:
Question 3:
Tick (✓) the correct answer
The value of (−2)−5 is
(a) −32
(b)
(c) 32
(d)
Answer:
(b)
Page No 37:
Question 4:
Tick (✓) the correct answer
(2−5 ÷ 2−2) = ?
(a)
(b)
(c)
(d)
Answer:
(d)
Page No 37:
Question 5:
Tick (✓) the correct answer
The value of (3−1 + 4−1)−1 ÷ 5−1 is
(a)
(b)
(c)
(d)
Answer:
(b)
Page No 37:
Question 6:
Tick (✓) the correct answer
(a)
(b)
(c) 29
(d)
Answer:
(c) 29
Page No 37:
Question 7:
Tick (✓) the correct answer
(a)
(b)
(c)
(d)
Answer:
(a)
Page No 37:
Question 8:
Tick (✓) the correct answer
(a)
(b) 16
(c)
(d) −16
Answer:
(a)
Page No 37:
Question 9:
Tick (✓) the correct answer
The value of x for which is
(a) −1
(b) 1
(c) 2
(d) 3
Answer:
(d) 3
Page No 37:
Question 10:
Tick (✓) the correct answer
If (23x − 1 + 10) ÷ 7 = 6, then x is equal to
(a) −2
(b) 0
(c) 1
(d) 2
Answer:
(d) 2
⇒
Therefore,
Page No 37:
Question 11:
Tick (✓) the correct answer
(a)
(b)
(c) 1
(d) 0
Answer:
(c) 1
Using the law of exponents :
Page No 38:
Question 12:
Tick (✓) the correct answer
(a)
(b)
(c)
(d) none of these
Answer:
(c)
Page No 38:
Question 13:
Tick (✓) the correct answer
(a)
(b)
(c)
(d)
Answer:
(d)
Page No 38:
Question 14:
Tick (✓) the correct answer
(a)
(b)
(c)
(d)
Answer:
(b)
Page No 38:
Question 15:
Tick (✓) the correct answer
3670000 in standard form is
(a) 367 × 104
(b) 36.7 × 105
(c) 3.67 × 106
(d) none of these
Answer:
(c)
Page No 38:
Question 16:
Tick (✓) the correct answer
0.0000463 in standard form is
(a) 463 × 10−7
(b) 4.63 × 10−5
(c) 4.63 × 10−9
(d) 46.3 × 10−6
Answer:
(b)
Page No 38:
Question 17:
Tick (✓) the correct answer
0.000367 × 104 in usual form is
(a) 3.67
(b) 36.7
(c) 0.367
(d) 0.0367
Answer:
(a) 3.67
Page No 39:
Question 1:
Evaluate:
(i) 3−4
(ii) (−4)3
(iii)
(iv)
(v)
Answer:
(i)
(ii)
(iii)
(iv)
(v) Using the property , we have:
Page No 39:
Question 2:
Evaluate:
Answer:
Page No 39:
Question 3:
Simplify:
Answer:
Page No 39:
Question 4:
By what number should be divided so that the quotient is ?
Answer:
Let the number be .
Page No 39:
Question 5:
By what number should (−3)−1 be multiplied so that the product becomes 6−1?
Answer:
Let the number be .
Page No 39:
Question 6:
Express each of the following in standard form:
(i) 345
(ii) 180000
(iii) 0.000003
(iv) 0.000027
Answer:
(i)
(ii)
(iii)
(iv)
Page No 39:
Question 7:
Mark (✓) against the correct answer
The value of (−3)−3 is
(a) −27
(b) 9
(c)
(d)
Answer:
(c)
Page No 39:
Question 8:
Mark (✓) against the correct answer
The value of is
(a)
(b)
(c)
(d)
Answer:
(b)
Page No 39:
Question 9:
Mark (✓) against the correct answer
(3−6 ÷ 34) = ?
(a) 3−2
(b) 32
(c) 3−10
(d) 310
Answer:
(c)
Page No 39:
Question 10:
Mark (✓) against the correct answer
If
(a) −1
(b) 1
(c) 2
(d) 3
Answer:
(d) 3
Page No 39:
Question 11:
Mark (✓) against the correct answer
(a)
(b)
(c) 1
(d) 0
Answer:
(c) 1
Using the law of exponents, which says we get:
Page No 39:
Question 12:
Mark (✓) against the correct answer
(a)
(b)
(c)
(d)
Answer:
(d)
Page No 39:
Question 13:
Mark (✓) against the correct answer
(a)
(b)
(c)
(d)
Answer:
(c)
Page No 40:
Question 14:
Fill in the blanks.
(i) 360000 written in standard form is .........
(ii) 0.0000123 written in standard form is .........
(iii)
(iv) 3 × 10−3 in usual form is .........
(v) 5.32 × 10−4 in usual form is .........
Answer:
(i) The standard form of 36000 is .
(ii) The standard form of 0.0000123 is .
(iii)
(iv)
(v)
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