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can any1 tell a+b+ c whole CUBE

crossword puzzles with mathematical terms with answers

what is the formula of (a+b+c) whole cube

prove that root 5 is an irrartional number using theory method!!!!

quick!!!!

if both x-2 and x-1/

_{2}are factors of px^{2}+5x+r show that p=rFactorise : x

^{3 }- 6x^{2}+ 11x -6 using FACTOR THEOREM.if x -1/x =3; then find the value of x

^{3}-1/x^{3}given that x

^{2}-x-2 is a factor of x^{3}+3x^{2}+ax+b calculate the values of a and b and hence find the remaining factorGive me a list of all the algebraic identities? Also the conditional identity.

Thumbs-Up Guaranteed.

1 )If a + b + c = 0 ( a

^{2 }/ bc ) + ( b^{2}/ ca ) + ( c^{2 }/ ab^{ }) = 32 ) Find the value of a ) 55

^{3 }- 25^{3 }- 30^{3 }b ) 99

^{3}if x+y+4 = 0 find the value of (x

^{3}+y^{3}-12xy+64)If a+b+c=6 and ab+bc+ca=11, find the value of a

^{3}+b^{3}+c^{3}-3abc.one of the factors of (1-3y)

^{2}+(9y^{2}-1) is:(A) (1-3y) ; (B) (3-y) ; (C) (3y+1) ;(D)( y-3)

^{4}-2x^{3}+3x^{2}-ax+b when divided by (x-1) and (x+1) leaves the remainders 5 and 19 respectively.find the values of a and b.hence,find the remainder when f(x) is divided by (x-2).simplify The following:

4th root of 12 * 7th root of 6

if x

^{4}+ 1/x^{4}= 47, then find the value of x^{3 }+ 1/x^{3}Factorise:

x

^{2}+1/x^{2}+2-2x-2/xIf (x+a) is a factor of two polynomials x2+px+q and x2+mx+n, then prove that :

a=n- q/m-pprove that

4x-5 is a factor of 36x square+29x-20

factorise:

x

^{3}+13x^{2}+32x+20 (by remainder theorem)if a teacher divides a material of volume (x^3+6x^2+12x+8) cubic units among three students of his class equally.is it possible to find the quantity of material each of them gets? Which moral value is depicted by the teacher?

How do we prove geometrically a

^{2-}b^{2 }= (a-b)(a+b)simplify factorise:- (a+b+c)whole square -(a-b-c)whole square +4b square +4c square

If x

^{2 }+ 1/x^{2}=7 then find value of x^{3 }+ 1/x^{3}^{2}- 4m +1 =0 evaluate m^{3}+ 1/m^{3}If x= 9+4 (root 5) then find (root x) - 1/ (root x)

PLeaseee answer fasst! needed at the moment! :)

A POLYNOMIAL HAVING TWO OR MORE THEN TWO TERMS IS CALLED A ---------

If a

^{2}+ b^{2}+ c^{2}ab - bc - ca = 0 , prove that a=b=c .(3Ycube-3/2ysquare+Ky+5) is exaxtly divisible by (Y-1/2) . show the calculation

Find the value of x

^{3}+y^{3}- 12xy + 64 when x + y = - 4evaluate

a

^{8}-47a^{4}+1^{}if x= 2+root3 then find the value of x

^{2}+ 1/x^{2}pl.. need the answer really fast................

p(x)=3x

Factorise x

^{3}+ y^{3}^{2}Factorise : x ( cube ) + y ( cube ) + z ( cube ) - 3xyz.

tell me fast friend's...

If x + 1/x = 3 , then find the value of x

^{2}+ 1/x^{2 }factorise

^{x4 +x2 +1 }Factorise :a

^{3}(b-c)^{3}+ b^{3}(c-a)^{3 }+c^{3}(a-b)^{3}factorize 8p

^{3}+12/5p^{2}+6/25p+1/125Factorise x

^{3}- 23x^{2}+ 142x - 120if x+y=5 and xy=4, find the value of x

^{3}+y^{3.}"If a+b+c = 0

Then a

^{3}+b^{3}+c^{3}= 3abc"Now what if a+b+c is

tonot equal, then how do you solve0?a^{3}+b+^{3}+c^{3}Solve this-

12^{3}+14^{3}+2^{3}.FACTORISE:

x

^{4}-125xy^{3}what is the whole cube of (x+y+z)

x3-23x2+142x-20

find the value of a and b, so that the polynomial (x

^{3}+10x^{2}+ax +b) is exactly by (x-1) as well as (x-2)when x3+3x2+3x+1 is divided by x-1/2

factorise: (x-y)

^{3}+(y-z)^{3}+(z-x)^{3}If x = -2 is the root of the equation root 2 (x + p) = 0 and is also the zero of the polynomial px to the power 2 + kx + 2 root 2 then find the value of k.

if a+b+c=0 then, a cube + b cube + c cube

if a+b+c=8, a

^{2}+b^{2}+c^{2}=30,find the value of ab+bc+caWithout actual division, prove that 2x

^{4}-5x^{3}-2x2 -x+2 is exactly divisible by x^{2}-3x+2y square + root 2 is a polynomial with 1 variable and 3 root "t" +"t' root 2 is a not a polynomial . can u plzzzz explain

may i pls get the ans :

1. find x if 2

^{x-5X}5^{x-4}=52.factorise : 6x

^{2}+5x-63.factorise : x

^{3}-3x^{2}-9x-54.x=2+root3 , find x

^{2}+1/x^{2}^{5. find the value of a and b 5+2root3/7+4root3=a+broot3}The value of k, for which the polynomial X

^{3}-3x^{2}+3x+k has 3 as its zero is?verify x3+y3=(x+y)(x2-xy+y2)

simplify (2x-y+z)^2-(2x+y-z)^2

√5 is a polynomial of degree ?

Without actually calculating, find the value of (25)^3 - (75)^3 + (50)^3

f (x )

1.4x2+2x-1

2.Y+3/y

3.X3-1

4.Y2+5y+1

If x+(1/x)=5, then evaluate x

^{6}+(1/x^{6})^{2}–k = (9y +1/2) (9y-1/2) then the value of kx

^{3}+y^{3}+z^{3}-3xyz = 1/2 (x+y+z)[(x-y)^{2}+(y-z)^{2}+(z-x)^{2}]what is the simplest rationalization factor of root 5 and why?kindly explain .

If a

^{1/3}+ b^{1/3}+ c^{1/3}= 0 thena) a+b+c=0

b) (a+b+c)

^{3}=27abcc) a+b+c=3abc

d) a

^{3}+b^{3}+c^{3}=0Also explain how ??

If 2x = t + root of (t

^{2}+4) and 3y = t - root of (t^{2}+4) and given that x = 2/3, then find the value of y.Find the remainder when

x^{3}+ 3x^{2}+ 3x+ 1 is divided by(i)

x+ 1 (ii) (iii)x(iv)

x+ π (v) 5 + 2xIf x-y = 5 and xy =84, then find the value of x cube - y cube

give the property

if a+b+c =5 and ab+bc+ca=10, then prove that a

^{3}+b^{3}+c^{3}-3abc= -25.Can you factorize this expression please, x

^{12 }- y^{12}= ?simplify: 1/ ( root3 + root2 - root5)

If (x-1/x) = 6, then find (x

^{2}+ 1/x^{2}) and (x + 1/x)I found (x

^{2}+ 1/x^{2}) = 38Now how to find (x + 1/x) ?

factorise it. x4 + x2 + 25

DIVIDE p(x)=3x

^{2}+x-1 by g(x)=x+1. I have solved this by long division method & got 3x^{2}-2 as quotient and 1 as remainder. My question is why we cannot use +2 instead of -2 in 3x^{2}-2??????If a+b = 10 and a

^{2}+ b^{2 }= 58 find the value of a^{3}+ b^{3}factorise :- x^8-y^8

if ax

^{3}+bx^{2}+x-6 has x+2 as factor and leaves the remainder 4 when divided by (x-2), find the values of 'a' and 'b' .A) 1&2

B) 2&3

C) 3&4

D) 0&1

Q- if x square + 1/ x square = 83 then find the value of x cube - 1/ x cube

(i) if both x-2 and x-1/2 are factors of px

^{2}+5x + r , show that p=r(ii)if the polynomial az

^{3}+4z^{2}+3z-4 and z^{3}-4z+a leave the same remainder when divided by z-3 find 'a'If(X

^{2}-1) is a factor of ax^{4}+bx^{3}+cx^{2}+dx+e,show that a+c+e=b+d=0what is nonnegative integral power

Prove that

ais always non-negative for all valuesof a, b and c.^{2}+b^{2}+c^{2}-ab-bc-ca