Rs Aggarwal 2021 2022 Solutions for Class 9 Maths Chapter 5 Coordinate Geometry are provided here with simple step-by-step explanations. These solutions for Coordinate Geometry are extremely popular among Class 9 students for Maths Coordinate Geometry Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2021 2022 Book of Class 9 Maths Chapter 5 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2021 2022 Solutions. All Rs Aggarwal 2021 2022 Solutions for class Class 9 Maths are prepared by experts and are 100% accurate.

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

(ix)

(x)

(xi)

(xii)

#### Page No 175:

Draw perpendicular AL, BM, CN, DP and EQ on the X-axis.

(i) Distance of A from the Y-axis = OL = -6 units
Distance of A from the X-axis = AL = 5 units
Hence, the coordinates of A are (-6,5).

(ii) Distance of B from the Y-axis = OM = 5 units
Distance of B from the X-axis = BM = 4 units
Hence, the coordinates of B are (5,4).

(iii) Distance of C from the Y-axis = ON = -3 units
Distance of C from the X-axis = CN = 2 units
Hence, the coordinates of C are (-3,2).

(iv) Distance of D from the Y-axis = OP = 2 units
Distance of D from the X-axis = DP = -2 units
Hence, the coordinates of D are (2,-2).

(v) Distance of E from the Y-axis = OL = -1 units
Distance of E from the X-axis = AL = -4 units
Hence, the coordinates of E are (-1,-4).

#### Page No 175:

(i) (–6, 3)
Points of the type (–, +) lie in the II quadrant.
Hence, the point lies (–6, 3) in the II quadrant.

(ii) (–5, –3)
Points of the type (–, –) lie in the III quadrant.
Hence, the point lies (–5, –3) in the III quadrant.

(iii) (11, 6)
Points of the type (+, +) lie in the I quadrant.
Hence, the point lies (11, 6) in the I quadrant.

(iv) (1, –4)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (1, –4) in the IV quadrant.

(v) (–7, –4)
Points of the type (–, –) lie in the III quadrant.
Hence, the point lies (–7, –4) in the III quadrant.

(vi) (4, –1)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (4, –1) in the IV quadrant.

(vii) (–3, 8)
Points of the type (–, +) lie in the II quadrant.
Hence, the point lies (–3, 8) in the II quadrant.

(viii) (3, –8)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (3, –8) in the IV quadrant.

#### Page No 175:

(i) (2, 0)
The ordinate of the point (2, 0) is zero.
Hence, the (2, 0) lies on the x-axis.

(ii) (0, –5)
The abscissa of the point (0, –5) is zero.
Hence, the (0, –5) lies on the y-axis.

(iii) (–4, 0)
The ordinate of the point (–4, 0) is zero.
Hence, the (–4, 0) lies on the x-axis.

(iv) (0, –1)
The abscissa of the point (0, –1) is zero.
Hence, the (0, –1) lies on the y-axis.

#### Page No 175:

(i) A(0, 8)
The given point does not lies on the x-axis.

(ii) B(4, 0)
The ordinate of the point (4, 0) is zero.
Hence, the (4, 0) lies on the x-axis.

(iii) C(0, –3)
The given point does not lies on the x-axis.

(iv) D(–6, 0)
The ordinate of the point (–6, 0) is zero.
Hence, the (–6, 0) lies on the x-axis.

(v) E(2, 1)
The given point does not lies on the x-axis.

(vi) F(–2, –1)
The given point does not lies on the x-axis.

(vii) G(–1, 0)
The ordinate of the point (–1, 0) is zero.
Hence, the (–1, 0) lies on the x-axis.

(viii) H(0, –2)
The given point does not lies on the x-axis.

#### Page No 175:

Abscissa of D = Abscissa of A = 2
Ordinate of D = Ordinate of B = 2

Now,
BC = (2 + 4) units = 6 units
AD = (5 – 2) units = 3 units

Hence, area of ∆ABC is 9 square units.

#### Page No 175:

Let A(3, 1), B(–3, 1) and C(–3, 3) be three vertices of a rectangle ABCD.

Let the y-axis cut the rectangle ABCD at the points P and Q respectively.

Abscissa of D = Abscissa of A = 3.
Ordinate of D = Ordinate of C = 3.

∴ coordinates of D are (3, 3).

AB = (BP + PA) = (3 + 3) units = 6 units.
BC = (OQOP) = (3 – 1) units = 2 units.

Ar(rectangle ABCD) = (AB × BC)
= (6 × 2) sq. units
= 12 sq. units

Hence, the area of rectangle ABCD is 12 square units.

#### Page No 176:

Points of the type (–, –) lie in the III quadrant.
The point (–7, –4) lies in the III quadrant.

Hence, the correct option is (c).

#### Page No 176:

(d) IV
​Explanation:
The points of the type (+,-) lie in fourth quadrant.
Hence, the point (x,y), where x > 0 and y < 0, lies in quadrant IV.

#### Page No 176:

Ans (b)

Explanation:
Points of the type (-,+) lie in the second quadrant.
Hence, the point P(a,b), where a < 0 and b > 0, lie in quadrant II.

#### Page No 176:

​Explanation:
Points of the type (-,-) lie in the third quadrant.

#### Page No 176:

(c) I or III

​Explanation:
If abscissa = ordinate, there could be two possibilities.
Either both are positive or both are negative. So, a point could be either (+,+), which lie in quadrant I or it could be of the type (-,-), which lie in quadrant III.
Hence, the points (other then the origin) for which the abscissas are equal to the ordinates lie in quadrant I or III.

#### Page No 176:

The point (–5, 3) lies in the II quadrant.
The point (3, –5) lies in the IV quadrant.

Hence, the correct option is (c).

#### Page No 176:

The point (1, –1) lies in the IV quadrant.
The point (2, –2) lies in the IV quadrant.
The point (–3, –4) lies in the III quadrant.
The point (4, –5) lies in the IV quadrant.

Hence, the correct option is (d).

#### Page No 176:

The abscissa of the point (0, –8) is zero.
The point (0, –8) lies on the y-axis.

Hence, the correct option is (d).

#### Page No 176:

The point (–7, 0) lies on the negative direction of the x-axis.

Hence, the correct option is (a).

#### Page No 177:

The point which lies on the y-axis at a distance of 5 units in the negative direction of the y-axis is (0, –5).

Hence, the correct option is (b).

#### Page No 177:

The ordinate of every point on the x-axis is 0.

Hence, the correct option is (c).

#### Page No 177:

The coordinates of a point on the x-axis are of the form (x, 0) and that of the point on the y-axis is of the form (0, y).

Thus, if the y-coordinate of a point is zero, then this point always lies on the x-axis.

Hence, the correct answer is option (b).

#### Page No 177:

The point O(0, 0) is the origin.

A(3, 0) lies on the positive direction of x-axis.

B(3, 4) lies in the Ist quadrant.

C(0, 4) lies on the positive direction of y-axis.

The points O(0, 0), A(3, 0), B(3, 4) and C(0, 4) can be plotted on the Cartesian plane as follows:

Here, the figure OABC is a rectangle.

Hence, the correct answer is option (b).

#### Page No 177:

The given points are A(–2, 3) and B(–3, 5).

Abscissa of A = x-coordinate of A = –2

Abscissa of B = x-coordinate of B = –3

∴ Abscissa of A – Abscissa of B = –2 – (–3) = –2 + 3 = 1

Hence, the correct answer is option (b).

#### Page No 177:

The perpendicular distance of a point from the y-axis is equal to the x-coordinate of the point.

∴ Perpendicular distance of the point A(3, 4) from the y-axis = x-coordinate of A(3, 4) = 3

Hence, the correct answer is option (a).

#### Page No 177:

​Explanation:
If abscissa of a point is positive, then the ordinate could be either positive or negative.
It means that the type of any point can be either (+,+) or (+, -).
Points of the type (+,+) lie in quadrant I, whereas points of the type (+,-) lie in quadrant IV.

#### Page No 177:

(c) the origin
​Explanation: The point at which two axes meet is called as the origin.

#### Page No 177:

The ordinate of a point is the y-coordinate of the point. So, the y-coordinate of the point is 3.

Also, any point on the y-axis has coordinates in the form (0, y).

Thus, the point whose ordinate is 3 and which lies on the y-axis is (0, 3).

Hence, the correct answer is option (b).

#### Page No 177:

(b) (3,9)

Explanation:
Point (2,8) does not satisfy the equation y = 2x + 3.              (​∵ y = 2 × 2 + 8 = 12$\ne$ 8)
Point (3,9) satisfy the equation y = 2x + 3.                             (​∵ y =2 × 3 + 3 = 9)
Point (4,12) does not satisfy the equation y = 2x + 3.    (∵ y = 2 × 4 + 3 = 11$\ne$ 12)
Point (5,15) does not satisfy the equation y = 2x +3.    (∵ y= 2 × 5 + 3 = 13$\ne$15)
Hence, the point (3,9) lies on the line ​y = 2x +3.

#### Page No 177:

(d) (4,12)

Explanation:
(a) Point (1,7) satisfy the equation y = 3x + 4.                      (∵y = 3 × 1 + 4 = 7)
(b) Point (2,10) satisfy the equation y = 3x + 4.                    (∵y = 3 × 2 + 4 = 10)
(c) Point (-1,1) satisfy the equation y = 3x + 4.                     (∵y = 3 × -1 + 4 = 1)
(d) Point (4,12) does not satisfy the equation y = 3x + 4.    (∵ y = 3 × 4 + 4 = 16 ≠ 12)
Hence, the point (4,12) do not lie on the line y = 3x +4.

#### Page No 177:

The point (3, –6) lies in the fourth quadrant.

The point (–3, 4) lies in the second quadrant.

The point (5, 7) lies in the first quadrant.

The point (0, 3) lies on the positive direction of y-axis.

Thus, the point (0, 3) does not lie in any quadrant.

Hence, the correct answer is option (d).

#### Page No 177:

The points A(0, 6), O(0, 0) and B(6, 0) can be plotted on the Cartesian plane as follows:

Here, ∆AOB is a right triangle right angled at O.

OA = 6 units and OB = 6 units

∴ Area of ∆AOB = $\frac{1}{2}×\mathrm{OA}×\mathrm{OB}=\frac{1}{2}×6×6$ = 18 square units

Hence, the correct answer is option (c).

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