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Syllabus

$8.\mathrm{In}\mathrm{the}\mathrm{adjoining}\mathrm{figure},\angle \mathrm{BCD}=\angle \mathrm{ADC}\mathrm{and}\angle \mathrm{BCA}=\angle \mathrm{ADB}.\mathrm{Show}\mathrm{that}.\phantom{\rule{0ex}{0ex}}\left(\mathrm{i}\right)\u25b3\mathrm{ACD}\cong \u25b3\mathrm{BDC}\phantom{\rule{0ex}{0ex}}\left(\mathrm{ii}\right)\mathrm{BC}=\mathrm{AD}\phantom{\rule{0ex}{0ex}}\left(\mathrm{iii}\right)\angle \mathrm{A}=\angle \mathrm{B}\phantom{\rule{0ex}{0ex}}$

angleAFE =137degree

Find the value of x and y (in the figure)

BG=21m,

AM=18m

DN=12.8m, and

ED=14m

Q. In the alongside diagram, the bisectors of interior angles of the parallelogram PQRS enclose a quadrilateral ABCD.

Show that :

(i) $\angle $PSB+$\angle $SPB = 90$\xb0$ (ii) $\angle $PBS = 90$\xb0$ (iii) $\angle $ABC = 90$\xb0$ (iv) $\angle $ADC = 90$\xb0$

(v) $\angle $A = 90$\xb0$ (vi) ABCD is a rectangle

and the distance between CB and DA

$\mathbf{10}\mathbf{.}\mathrm{In}\mathrm{the}\mathrm{given}\mathrm{figure},\mathrm{ABCDE}\mathrm{is}\mathrm{a}\mathrm{pentagon}\mathrm{inscribed}\mathrm{in}\mathrm{a}\mathrm{circle}.\mathrm{If}\mathrm{AB}=\mathrm{BC}=\mathrm{CD},\angle \mathrm{BCD}=110\xb0\mathrm{and}\angle \mathrm{BAE}=120\xb0,\mathrm{find}:\phantom{\rule{0ex}{0ex}}\left(\mathrm{i}\right)\angle \mathrm{ABC}\left(\mathrm{ii}\right)\angle \mathrm{CDE}\left(\mathrm{iii}\right)\angle \mathrm{AED}\left(\mathrm{iv}\right)\angle \mathrm{EAD}$

Q. ABCD is a rectangle. If $\angle $BPC = 124$\xb0$. Calculate : (i) $\angle $BAP (ii) $\angle $ADP

Q.4. Is it possible to construct a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 5.5 cm, DA = 6 cm and BD = 9 cm? If not, give reason.

Q 2. The diagonals of a quadrilateral intersect each other at right angles. If the lengths of these diagonals be 14 cm and 19 cm respectively, find the area of the quadrilateral.Q 3. Find the area of quadrilateral ABCD in which AB= 29 cm, BC= 21 cm, AC= 20 cm, CD= 34 cm and DA= 42 cm.It's urgent . experts please answer fast ....

please send pics of solution don't do typing on brainly..

the person who will answer will be genius.......