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Syllabus

the perpendicular distance between the pair of opposite sides of a parellelogram are 3cm and 4cm and one of its angle measures 60 degree.construct a parellelogram.

plz answer fast

Q.2. AB = 7.2 cm, BC = 5.8 cm, CD = 6.3 cm, AD = 4.3 cm and angle A = 75$\xb0$.

Q. BC = 7.5 cm, AC = 5.8 cm, AD = 3.6 cm, CD = 4.2 cm and angle A = 120$\xb0$.

^{2 }and base= 4.8cm^{0}and height=3.0cmAB=CD=3 cm,BC=5.2 cm AD=4 cm and

AD||BC

3. In the adjoining figure, AD = BC, P, Q, R and S are mid-points of AB, BD, CD and AC respectively. Prove that PQRS is a rhombus.

Q.6. Construct a quadrilateral ABCD, when :

AD = AB = 4 cm, BC = 2.8 cm, CD = 2.5 cm and angle BAD = 45$\xb0$.

Construct a quadrilateral ABCD, when:

7. Ab=6.3 cm, BC=CD=4.2 cm and $\angle $ABC=$\angle $BCD=90

^{o}.Q. Construct a quadrilateral ABCD, when :

4. AB = 3.8 cm, AC = 4.8 cm, AD = 2.8 cm, angle A = 105$\xb0$ and angle B = 60$\xb0$.

Q. AD = AB = 4 cm, BC = 2.8 cm, CD = 2.5 cm and angle BAD = 45$\xb0$.

Q. AB = 3.8 cm, AC = 4.8 cm, AD = 2.8 cm, angle A = 105$\xb0$ and angle B = 60$\xb0$.

3. Angle A=90

^{o}, AB=4.6 cm, BD=6.4 cm, AC=0.6 cm and CD=4.2 cm.4. AB=3.8cm, AC=4.8 cm, AD=2.8 cm, angle A=105

^{o}and angle B=60^{o}Solve this:1. AB=3.2 cm,BC=5.2 cm

CD=6.2 cm, DA=4.2 cm and BD=5.2 cm

6 cm and height equals to 3.5 cm

Q. AB = 6.3 cm, BC = CD = 4.2 cm and $\angle ABC=\angle BCD=90\xb0$.

Q.20. Construct a trapezium ABCD, when :

AB = 4.8 cm, BC = 6.8 cm, CD = 5.4 cm, $\angle B=60\xb0andAD\parallel BC$.