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Syllabus

4

^{x-1}x (0.5)^{3-2x}= (1/8)^{-x}i) log 5 + log 20 + log 24 + log 25 – log 60

ii) log 6 + 2 log 5 + log 4 – log 3 – log 2

^{x}.3^{y}.5^{z}=2160 then find the value of x,y and z._{pi }[log_{2}(log_{7}x)] = 0(c) In figure (3) given below, ABCD is a rhombus. Find the value of x.

I have been asking for the answer in the last two questions also but the first answer was incorrect and the second EXPERT gives out unwanted links to just seperate questions at all . Please answer it properly because the EXPERT'S answers are INCORRECT

5. Given log

_{10}a=b, express 10^{2b-3}in terms of a.6. Given log

_{10}x=a, log_{10}y=b and log_{10}z=c,$\left(\mathrm{i}\right)\mathrm{Write}\mathrm{down}{10}^{2\mathrm{a}-3}\mathrm{in}\mathrm{terms}\mathrm{of}\mathrm{x}.\phantom{\rule{0ex}{0ex}}\left(\mathrm{ii}\right)\mathrm{Write}\mathrm{down}{10}^{3\mathrm{b}-1}\mathrm{in}\mathrm{terms}\mathrm{of}\mathrm{y}.\phantom{\rule{0ex}{0ex}}\left(\mathrm{iii}\right)\mathrm{If}\mathrm{log}{}_{10}\mathrm{P}=2\mathrm{a}+\frac{\mathrm{b}}{2}-3\mathrm{c},\mathrm{express}\mathrm{P}\mathrm{in}\mathrm{terms}\mathrm{of}\mathrm{x},\mathrm{y}\mathrm{and}\mathrm{z}.$

(i) $3\left({2}^{x}+1\right)-{2}^{x+2}+5=0$

log

_{10}(x + 2 ) + log_{10}(x-2) + log_{10}3 + 3 log_{10}4Given log

_{10}x = 2a and log_{10}y = b/2,if log

_{10}P = 3a - 2b, express P in terms of x and y.6. Given log

_{10}x=a, log_{10}y=b and log_{10}z=c,(i) Write down 10

^{2a-3}in terms of x.(ii) write down 10

^{3b-1}in terms of y.(iii) if ${\mathrm{log}}_{10}\mathrm{P}=2\mathrm{a}+\frac{\mathrm{b}}{2}-3\mathrm{c}$, express P in terms.

I SEND THIS QUESTION MANY TIMES BUT TILL TODAY I HAVEN'T GOT THE ANSWER FOR THE QUESTION.CAN YOU PLEASE SEND ME THE ANSWER NOW AS MY 1ST SEMESTER EXAM IS STARTING SOON.?

Easy?Multiple Choice Question On The Topic Of Logarithms With Answers

? ?

? ? ? "PLEASE DON'T ?SEND THE CHAPTER'S LINK.KINDLY SEND THE FOLLOWING QUESTIONS WITH ANSWER"

31. Solve for x:

(i) log

_{3}x + log_{9}x + log_{81}x = $\frac{\text{7}}{\text{4}}$^{-p}= 4^{-q}= 20^{r}, then show that:1/p + 1/q +1/r = 0