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4

^{x-1}x (0.5)^{3-2x}= (1/8)^{-x}_{pi }[log_{2}(log_{7}x)] = 0^{x}.3^{y}.5^{z}=2160 then find the value of x,y and z.(c) In figure (3) given below, ABCD is a rhombus. Find the value of x.

(8x^4) ^1/3?x^1/3

(i) $3\left({2}^{x}+1\right)-{2}^{x+2}+5=0$

i) log 5 + log 20 + log 24 + log 25 – log 60

ii) log 6 + 2 log 5 + log 4 – log 3 – log 2

Q.11. If $m\ne nand{\left(m+n\right)}^{-1}\left({m}^{-1}+{n}^{-1}\right)={m}^{x}{n}^{y}$; show that : x + y + 2 = 0.

^{1/3}+a^{-1/3})(a^{2/3}-1+a^{-2/3}) please solve5. Given log

_{10}a=b, express 10^{2b-3}in terms of a.6. Given log

_{10}x=a, log_{10}y=b and log_{10}z=c,$\left(\mathrm{i}\right)\mathrm{Write}\mathrm{down}{10}^{2\mathrm{a}-3}\mathrm{in}\mathrm{terms}\mathrm{of}\mathrm{x}.\phantom{\rule{0ex}{0ex}}\left(\mathrm{ii}\right)\mathrm{Write}\mathrm{down}{10}^{3\mathrm{b}-1}\mathrm{in}\mathrm{terms}\mathrm{of}\mathrm{y}.\phantom{\rule{0ex}{0ex}}\left(\mathrm{iii}\right)\mathrm{If}\mathrm{log}{}_{10}\mathrm{P}=2\mathrm{a}+\frac{\mathrm{b}}{2}-3\mathrm{c},\mathrm{express}\mathrm{P}\mathrm{in}\mathrm{terms}\mathrm{of}\mathrm{x},\mathrm{y}\mathrm{and}\mathrm{z}.$

7^(1/2) - 8^(1/2)

Please do not provide any link.

Please solve as soon as you can as our exams are starting soon.

Q.38. Find the value of a, (a $\in $ integer) if :

${2}^{a-5}\times {6}^{2a-4}=\frac{1}{{12}^{4}\times 2}$.

I SEND THIS QUESTION MANY TIMES BUT TILL TODAY I HAVEN'T GOT THE ANSWER FOR THE QUESTION.CAN YOU PLEASE SEND ME THE ANSWER NOW AS MY 1ST SEMESTER EXAM IS STARTING SOON.?

Easy?Multiple Choice Question On The Topic Of Logarithms With Answers

? ?

? ? ? "PLEASE DON'T ?SEND THE CHAPTER'S LINK.KINDLY SEND THE FOLLOWING QUESTIONS WITH ANSWER"

5th sum pls

Given log

_{10}x = 2a and log_{10}y = b/2,if log

_{10}P = 3a - 2b, express P in terms of x and y.iv) $\frac{\text{log8}}{\text{log2}}\text{\xd7}\frac{\text{log}{\displaystyle \text{3}}}{\text{log}{\displaystyle \sqrt{\text{3}}}}$=2 logx.

^{-p}= 4^{-q}= 20^{r}, then show that:1/p + 1/q +1/r = 0

31. Solve for x:

(i) log

_{3}x + log_{9}x + log_{81}x = $\frac{\text{7}}{\text{4}}$6th sum pls