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Syllabus

By elimination by substitution

2/x - 1/y = 1

Solve by reducing them to pairs of linear equations

Please explain the steps...

5x-3y=2

4x+7y=-3

Experts please answer it urgent.

30. A boat sails a distance of 44 km in 4 hours with the current. It takes 4 hours 48minute longer to cover the same distance against the current. Find the speed of boat on still water and the speed of the current.

0.2x + 0.1y = 25

2 (x - 2) - 1.6y = 116

Plz solve this question by linear equations.

Take no. of customers as 'x' & no. of lines as 'y'.

Find x & y

3x-4y+6=0

Please tell question no.9

Q9. The ratio of two numbers is $\frac{2}{3}$. If 2 is subtracted from the first and 8 from the second, the ratio becomes the reciprocal of the original ratio. Find the numbers.

${\left(\frac{81}{16}\right)}^{-\frac{3}{4}}\times \left[{\left(\frac{25}{9}\right)}^{-\frac{3}{2}}\xf7{\left(\frac{5}{2}\right)}^{-3}\right]$

If the digits are reversed, the new no. decreased by 9 is equal to 4 times the original no. Find the original no.

(27/8)

^{2/3}- (1/4)^{-2}+ 5^{0}Q. The sides of an equilateral triangle are (6x + 3y) cm, (8x + 9y - 5) cm and (10x + 12y - 8) respectively. Find the length of each side.

[

Hint.Take 6x + 3y = 8x + 9y - 5 and 8x + 9y - 5 = 10x + 12y - 8 as two equations.]4x - 3y = -1

Find p, if y = px - 3

Linear Equations by substitutional method

33. A man travels 600km partly by train and partly by car. If he covers 120km by train and the next by car, it takes him 8 hours. But, if he travels 200km by train and the rest by car he takes 20 minutes longer. Find the speed of the car and that of the train.

Q. 2x + 3y = 17

3x - 2y = 6

3x-5y=4

9x-2y=7

$40.\mathrm{Solve}:\frac{15}{\mathrm{u}}+\frac{2}{\mathrm{v}}=17\mathrm{and}\frac{1}{\mathrm{u}}+\frac{1}{\mathrm{v}}=\frac{36}{5}$

11x+13y=74

Method of elimination by equating coefficient

5/x-3/y=1-[2]

Question on simultaneous linear equation

Solve this by reducible to pair of equation method and cross multiplication method.

3/x + 4y = 7

5/x + 6y = 13

Q.48. 8 men and 12 boys can finish a work in 10 days while 6 men and 8 boys can finish the same work in 14 days. Find the time taken by 1 man and that 1 boy alone to finish the work.

3/x + 4y =7. 5/x + 6y =13