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Syllabus
30. Using the measurements given in figure alongside,
(a) find the values of :
(1) sin (ii) tan .
(b) write an expression for AD in terms of .
Hint: (b) CD = 5. Draw DE perpendicular to AB, BE = 5, EA = 9.
Q.37. In the following figure, AB = 4 cm and ED = 3 m.
If find the length of BD.
(a) 2 (b) 1 (c) 0 (d) None of these.
(xxii) If tan + cot = 2, then the value of tan - cot is
(a) 1 (b) 2 (c) - 1 (d) None of these.
(xxiii) If 3 cos - 4 sin = 5, then the value of 3 sin + 4 cos is
(a) 1 (b) 2 (c) 0 (d) None of these.
i) cos angle CBD
ii) cot angle ABD
7. Find AB.
m = a sec A + b tan B
n = a tan A + b sec A
Prove that : m^2 - n^2 = a^2 - b^2
Q12. If
Q13. If
Q14. If
Q12. Without using trigonometrical tables, evaluate :
(i) (ii)
(iii) sin234° + sin256° + 2 tan 18° tan 72° – cot2 30°.
Q13. Prove the following :
(i)
(ii) cos
(iii) .
Q14. Prove the following :
(i)
(ii)
Q15. Simplify the following :
(i)
)=1 solve for x1. (Cos 13 + sin 13)/ (cos 13 - sin 13) = tan A
What is A?
2. (sin 20 cos 70 + cos 20 sin 70)/ (sin 23 cosec 23 + cos 23 sec 23)= ?
3. If tan a = 5/6 and tan b = 1/11, then what is the value of a + b ?
o=6 sino, evaluate:oo-3 coso\12 sino+3 coso8 (c) In the figure (3) given below, AD is perpendicular to BC, BD=15 cm, sin B= and tan C=1
(i) Calculate the lengths of AD, AB, DC and AC.
Q7. In what time will Rs.2400 amount to Rs. 2646 at 10% p.a. compounded half yearly.
(i) sin A (ii) cos A (iii) tan C
(cosec A/ cosec A - 1) (cosec A/ cosec A + 1) = 2 sec ^2 A
Find
(a)tanx
(b)sinx
Q.4. Prove that
(ii).
Q6. If 3 is an acute angle, solve the following equation for :
(cosec 3 – 2) (cot 2 – 1) = 0.