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Syllabus
Q. A micrometer screw gauge has a negative error of 0.008 cm. While measuring the diameter of a wire, the reading on the main scale is 3 divisions and the 24th circular scale division coincides with the baseline. If the number of divisions on the main scale are 20 and circular scale has 100 divisions, calculate the:
(a) pitch of the screw gauge. [Ans. 0.1 cm]
(b) least count of the screw gauge. [Ans. 0.001 cm]
(c) observed diameter of the wire. [Ans. 0.174 cml
(d) corrected diameter of the wire. [Ans. 0.182 cm]
[Ans. a. 0.837 cm, b. 0.555 cm]
a.
b.
(a) nanometer
(b) metre
Answer is (a) 580nm
(b) 5.8 ?10to the power -7
Wire;____?
Pls I need the process to understand it
Here is the hint and answer in my book
Q.11. How is the zero error of a screw gauge determined?
10. Two simple pendulums A and B have equal length, but their bobs weight 50 gf and 100 fg respectively. What would be the ratio of their time periods ? Given reason for your answer.
1-nanometre
2-millimetre
3-centimetre