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Syllabus

(a) nanometer

(b) metre

Answer is (a) 580nm

(b) 5.8 ?10to the power -7

Q. A micrometer screw gauge has a negative error of 0.008 cm. While measuring the diameter of a wire, the reading on the main scale is 3 divisions and the 24th circular scale division coincides with the baseline. If the number of divisions on the main scale are 20 and circular scale has 100 divisions, calculate the:

(a) pitch of the screw gauge. [Ans. 0.1 cm]

(b) least count of the screw gauge. [Ans. 0.001 cm]

(c) observed diameter of the wire. [Ans. 0.174 cml

(d) corrected diameter of the wire. [Ans. 0.182 cm]

1-nanometre

2-millimetre

3-centimetre

[Ans. a. 0.837 cm, b. 0.555 cm]

a.

b.

Wire;____?

Pls I need the process to understand it

Here is the hint and answer in my book

Q.11. How is the zero error of a screw gauge determined?

1 century=3.16?10^9 second and not

3.15?10^9s?

10. Two simple pendulums A and B have equal length, but their bobs weight 50 gf and 100 fg respectively. What would be the ratio of their time periods ? Given reason for your answer.

Note: only defination (in simple words, but appropriate)

Q. The mass of an oxygen atom is 16.00 $\mu $. Find its mass in kg.