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Syllabus
a.a1/a2=b1/b2=c1/c2
b.a1/c2=b1/b2=c1/a2
c.a1a2=b1b2=c1c2
d.none of these
Options :
A) 1 B) 2 C) 4 D) infinite
I don't know to which chapter it belongs, it's in a book for KVPY
Illustration 2.79 In equation x4-2x3+4x2+6x-21=0 if two of its roots are equal in magnitude but opposite in sign. find the roots.
1) 4
2) 3
3) 2
4) 1
5. Let f(x), g(x), and h(x) be the quadratic polynomials having positive leading coefficients and real and distinct roots. If each pair of them has a common root, then find the roots of
f(x) + g(x) + h(x) = 0.
mod(2x-3)<mod(x+2) is ?
log224/ log962-log2192 /log122
I can understand up to ---2log0.3(x-1)<log0.3(x-1)
(x-1)2>(x-1) --- next step sign changed from < to >. Can you please explain sir
a.(-infinity,4) b.(-infinity,2) c.(-infinity,3) d.(-infinity,1)
a) b2 >4ac b) c>0 c) c<0 d) none of these
[1] x2 - 2ax + a2 - b2 - c2 = 0
[2] (a - b + c)*x2 + 4(a- b)*x +(a- b -c) = 0
?
If a1, a2 and b1, b2 are roots of the equation
2x2+3x+k1=0and x2+2x+k2=0 respectively, then the system of equation a1y+a2z=0 and b1y+b2z=0 has a non zero solution. What will be the value of k1:k2?
|x-1| ≥ |x-3|
Find the values of m for which the equation sin^2x-(m-3)sinx+m=0 has real roots.
I can assume sinx to be t and reduce the equation to simple for. now t is binded in the interval -1,1. Now how to do sir? please clear!
find value of x