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Syllabus

^{2}-4xy+y^{2}=0 is?^{2}/2bc) (b^{2}/2ca) (c^{2}/2ab)=?^{2 }= 1/a^{2 }+ 1/b^{2}.[answer:4rt2]

2x-3y+5=0(a) In slope - intercept form and hence find slope & Y-intercept

(b) In intercept form and hence find intercept on axes.

(c) In normal form and hence find perpendicular distance from the origin and angle made by the perpendicular with the positive x-axis.

_{1}x and y=m_{2}_{}x for two of its sides,where m_{1}and m_{2}are the roots of the equation x^{2}+ax-1=0,then find the orthocentre of triangle^{2}+b^{2}+c2 = 3abc , then the line ax + by +c = 0 passes through ?Find the equation of angle bisectors of the pair of lines given by:

x

^{2}+4xy+y^{2}=0.(1) exactly one value of λ. (2) exactly two values of λ. (3) exactly three values of λ. (4) infinitely many values of λ.

^{2}-xy+4cy^{2}=0 is 3x+4y=0,then c=?

^{2}-2xy-y^{2}=0 with x-axis is?How to determine the slope from the given equation .? is it co-efficient of y/co-efficient of x...or minus of co-efficient of y/co-efficient of x..??? plzz. answer fast(A) 3 (B) 6 (C)8 (D) 12

l=>_{1}5x-y+4=0, l, l_{2}=> 3x-y+5=0_{3}=> x+y+8=0 as the sides of a triangle. Find tangents of interior angle. Also find the nature of the triangle.x+5y+10=0; 5x+y+10=0; x-5y-10=0; 5x-y-10=0