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Syllabus

Three thermochemical equations are given below:

$\left(i\right){C}_{\left(graphite\right)}+{O}_{2}\left(g\right)\to C{O}_{2}\left(g\right);{\u25b3}_{r}H\xb0=xkJmo{l}^{-1}\phantom{\rule{0ex}{0ex}}\left(ii\right){C}_{\left(graphite\right)}+\frac{1}{2}{O}_{2}\left(g\right)\to CO\left(g\right);{\u25b3}_{r}H\xb0=ykJmo{l}^{-1}\phantom{\rule{0ex}{0ex}}\left(iii\right)CO\left(g\right)+{O}_{2}\left(g\right)\to C{O}_{2}\left(g\right);{\u25b3}_{r}H\xb0=zkJmo{l}^{-1}\phantom{\rule{0ex}{0ex}}$

Based on the above equations, find out which of the relationship given below is correct:

(1) x = y - z

(2) z = x + y

what wiould be the temp. rise if 200ml of each liquid are mixed??

1)5degree

2)10degree

3)0.5

4)0.10degree

2.When an ideal gas is compressed adiabatically and reversibly, the final temperature is(1) Higher than the initial temperature

(2) Lower than the initial temperature

(3) The same as the initial temperature

(4) Dependent on the rate of compression

Propane (C

_{3}H_{8)}is used for heating water for domestic supply. assume that for 150kg of hot water supply per day must be heated from 10^{o}C to 65^{o}C. What moles of propane is used for heating this amount of water ?(Delta

_{c}H for propane = -2050 KJ/mol , c for water = 4.184 x 10^{-3 )}_{2}+ O_{2}--> 2H^{2}O is 574kJ . what is the heat of formation of waterstretching of rubber band

combustion of methane gas

diamond----> graphite

all of these

QUESTION NO 17Q17.

$\mathrm{Given}\mathrm{that}\mathrm{C}+{\mathrm{O}}_{2}\to {\mathrm{CO}}_{2},\u2206\mathrm{H}\xb0=-\mathrm{x}\mathrm{KJ}\phantom{\rule{0ex}{0ex}}2\mathrm{CO}+{\mathrm{O}}_{2}\to 2{\mathrm{CO}}_{2},\u2206\mathrm{H}\xb0=-\mathrm{y}\mathrm{KJ}$

what is heat of formation of CO?

(1) $\frac{\mathrm{y}-2\mathrm{x}}{2}$ (2) 2 x – y

(3) y – 2x (4) $\frac{2\mathrm{x}-\mathrm{y}}{2}$

What is the meaning of thermodynamic function?

$\mathbf{22}\mathbf{.}When1gofanhydrousoxalicacidisburntat25\xb0C,theamountofheatliberatedis2.835kJ.\u2206Hcombustionis(oxalicacid:{C}_{2}{H}_{2}{O}_{4})\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\left(1\right)-255.15kJ\left(2\right)-445.65kJ\phantom{\rule{0ex}{0ex}}\left(3\right)-295.24kJ\left(4\right)-155.16kJ$

QUESTION NO 11^{}^{st }reaction is used to carry out 2^{nd} reaction getting confused plzzz helpW=0

change in E=0

q=0

change in V=0