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Syllabus

_{1},a_{2},a_{3},a_{4},a_{5}) denote a rearrangement of (3,-5,7,4,-9) then the equation a_{1}x^{4}+a_{2}x^{3}+a_{3}x^{2}+a_{4}x+a_{5}=0 has how many roots?1. log 9/5+log 15/9-log 3/2=log 2

2. 2 log 3/7+log 49/9=0

3. log

_{b*c}a=log_{b}a/1+log_{b}c_{(3x + 5)}(6x^{2}+19x + 15) + log_{(2x + 3)}(9x^{2}+ 30x +25) = 4(1) $\frac{2{\mathrm{log}}_{3}2}{2{\mathrm{log}}_{3}2-1}$ (2) $\frac{2}{2-{\mathrm{log}}_{2}3}$ (3) $\frac{1}{1-{\mathrm{log}}_{4}3}$ (4) $\frac{2{\mathrm{log}}_{2}3}{2{\mathrm{log}}_{2}3-1}$

^{2}-8ax+a, the statements which hold good is/are(multiple correct answers)give explaination

a.) there is only one integral 'a' for which f(x) is non-negative for all x belongs to R

b.) for a< 0, the number lies between the zeroes of the polynomial

c.) f(x) =0 has two distinct solutions in (0,1) for 'a' belonging to (1/7,4/7)

d.) the minimum value of f(x) for minimum value of 'a' for which f(x) is non-negative for all x in R is zero

1. log

_{b2}a^{2}.log_{c2}b^{2}.log_{a2}c^{2}=12. Solve 213.768*4.434 whole divided by 6.321 using log table.

(1) 3 (2) 4

(3) 5 (4) 6

(213.768*4.434)/6.321

If 2

^{n} - 2^{m} = 960 , then n - m = ?