Go to Call Me

Have a query? Let us call you for FREE

X

+91

E.g : 9884012345, 01123456789

CALL NOW

Office hours: 9:00 am to 9:00 pm IST (7 days a week)

OOPS! We could not find any topic named

Select a subject to see full topic list

    find the greatest number which divides 632 and 2561 leaving remainder 7 and 11 respectively

    Dear student,
    On dividing 632 by the required number, remainder is 7
    ∴ 632-7 = 627 which will be exactly divided by the required number
    Similarly,
    2561-11=2550 will also be exactly divided by the required number
    so the required number is HCF of 638 & 783
    Prime factorization of 625 is 5 x 5 x 5 x 5 
    Prime factorization of 2550 =2, 3, 5, 5, 17
    HCF of 625 and 2550 is 5x5=25
    ∴ the required greatest number which divides 632 and 2550 leaving a remainder 7 and 11 respectively is 25
    Regards

    • 1
    View Full Answer