The hungry cat is trying to catch Kunjan the mouse. Kunjan is now on the 14th step and it can jump 2 steps at a time. The cat is on the third step. She can jump 3 steps at a time. If the mouse reaches 28 it can hide in the hole. Find out whether the mouse can get a way safely!
(a) The steps on which the mouse jumps ― ____________________
(b) The steps on which the cat jumps ― ______________________
(c) The steps on which both the cat and the mouse jump ―
(a) The steps on which the mouse jumps ― 16, 18, 20, 22, 24, 26, 28
(b) The steps on which the cat jumps ― 6, 9, 12, 15, 18, 21, 24, 27
(c) The steps on which both the cat and the mouse jump ― 18 and 24
(d) Yes, the mouse can get away.
If the cat starts from 5th step, and jumps 5 steps at a time, the cat will reach 10, 15, 20 and 25 steps.
If the mouse starts from 8th step, and jumps 4 steps at a time, the mouse will reach 12, 16, 20 and 24 steps.
So, the cat will easily be able to catch the mouse at step 20.
This time, the mouse cannot get away.
Mark with a red dot all the numbers which can be divided by 2.
Mark a yellow dot on the numbers which can be divided by 3 and a blue dot on the numbers which can be divided by 4.
Which are the boxes which have dots of all three colours?
What are the letters on top of those boxes?
Write those letters below in order.
Boxes 12, 24, 36, 48 and 60 have dots of all the 3 colours.
Letters on top of those boxes are M, O, U, S and E.
Letters in order will be E, M, O, S and U.
To play this game, everyone stands in a circle. One player calls out 'one'. The next player says 'two' and so on. A player who has to call out 3 or a number which can be divided by 3 has to say 'Meow' instead of the number. One who forgets to say 'Meow' is out of the game. The last player left is the winner.
Which numbers did you replace with 'Meow'?
3, 6, 9..............................
The numbers replaced by word "Meow" are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30 and so on.
We say these numbers are the multiples of 3.
Play the game by changing the number to 4.
Now, which numbers did you replace with 'Meow'?
These numbers are the multiples of 4.
• Write any ten multiples of 5.
Numbers that get replaced with "Meow" are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40 and so on.
Ten multiples of 5 are:
|5, 10, 15, 20, 25, 30, 35, 40, 45 and 50.|
Throw two dice together. What are the numbers that turn up on the faces of the dice? Make a two-digit number using them. If it is a multiple of any of the numbers written next to the circles, you can write it in that circle.
Disclaimer: The answer may vary from student to student, based on his/her observation. It is highly recommended that the students prepare the answer on their own.
Think of a number. If it is a multiple of 3 write it in the red circle. If it is a multiple of 5 write it in the blue circle.
Disclaimer: The answer may vary from student to student, based on his/her observation. It is highly recommended that the students prepare the answer on their own. The answer provided here is for reference only.
If you write the multiples common to 3 and 5 in the purple part, then will they still be in both the red and the blue circles?
• Which is the smallest among these common multiples? _________
Repeat the game using the numbers 2 and 7.
• Write the common multiples of 2 and 7.
Disclaimer: The answer of the first part of the question may vary from student to student, based on his/her observation. It is highly recommended that the students prepare the answer on their own. The answer provided here is for reference only.
Putting the multiples of 4, 6 and 5 in the circles.
• What common multiples of 5 and 6 did you write in the green part?
• What common multiples of 4 and 6 are written in the orange part?
• In which coloured part did you write the common multiples of 4, 6 and 5?
• What is the smallest common multiple of 4, 6 and 5? ________
Sunita took some tamarind (imli) seeds. She made groups of five with them, and found that one seed was left over. She tried making groups of six and groups of four. Each time one seed was left over. What is the smallest number of seeds that Sunita had?
We know, that if we make groups of 4, 5 and 6, each time we will be left with 1 seed.
So, we calculate the LCM of 4, 5 and 6 and add 1 to it.
Thus, the LCM of (4, 5, 6) = 60
Adding 1 to it, we get 61.
So, the smallest possible number of seeds that Sunita had is 61.
Ammini is arranging 12 tamarind seeds in the form of different rectangles. Try to make more rectangles like this using 12 tamarind seeds. How many different rectangles can you make?
Different rectangles that can be made from 12 tamarind seeds are as follows:
Thus, we can make five different rectangles.
If there are 15 tamarind seeds how many rectangles can you make?
We can make two rectangles from 15 tamarind seeds in the following way:
Thus, we can make two rectangles.
Colouring the Grid
In the grid here, a rectangle made of 20 boxes is drawn. The width of this rectangle is 2 boxes.
• What is its length?
• Colour a rectangle made of 20 boxes in some other way.
• What is the length and width of the rectangle you coloured?
• In how many ways can you colour a rectangle of 20 boxes? Colour them all in the grid, and write the length and width of each rectangle you have coloured.
There are 18 bangles on the rod. Meena is trying to group them. She can put them in groups of 2, 3, 6, 9 and 18 ― without any bangle being left.
• How many groups will she have if she makes groups of 1 bangle each? _____
Now complete the table, for different numbers of bangles. For each number see what different groups can be made.
|Different groups we can make|
|18||1, 2, 3, 6, 9, 18|
|24||1, 2, ...............|
|Different groups we can make|
|18||1, 2, 3, 6, 9, 18|
|24||1, 2, 3, 4, 6, 8, 12, 24|
|9||1, 3, 9|
|10||1, 2, 5, 10|
|20||1, 2, 4, 5, 10, 20|
|21||1, 3, 7, 21|
Complete the multiplication chart given here.
Look at the green boxes in the chart. These show how we can get 12 by multiplying different numbers.
|4 × 3
6 × 2
1 × 12
|5 × 2
_ _ _
|5 × 2
1 × 10
|2 × 18
3 × 12
1 × 36
4 × 9
6 × 6
Write the factors of 25 in the red circle and the factors of 35 in the blue circle.
Which are the factors you have written in the common part (purple) of both circles? These are common factors of 25 and 35.
1 and 5 are the common factors of 25 and 35. Thus, it is written in the common part of both the circles.
Now write the factors of 40 in the red circle and 60 in the blue circle.
Look at the factor tree. Now can you make another tree like this?
• In how many ways can you draw a factor tree for 24? Draw three of them below.
There is a garden in Anu's house. In the middle of the garden there is a path. They decided to tile the path using tiles of length 2 feet, 3 feet and 5 feet.
The mason tiled the first row with 2 feet tiles, the second row with 3 feet tiles and the third row with 5 feet tiles. The mason has not cut any of the tiles. Then what is the shortest length of the path?
Multiples of 2 = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30
Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30
Multiples of 5 = 5, 10, 15, 20, 25, 30
Smallest common multiple is 30.
So, the shortest length of the path is 30 m.
Manoj has made a new house. He wants to lay tiles on the floor. The size of the room is 9 feet × 12 feet. In the market, there are three kinds of square tiles: 1 foot × 1 foot, 2 feet × 2 feet and 3 feet × 3 feet. Which size of tile should he buy for his room, so that he can lay it without cutting?
Size of the room = 9 feet × 12 feet.
And there are 3 kinds of square tiles, 1 foot × 1 foot, 2 feet × 2 feet and 3 feet × 3 feet.
Now, size of tile that he should choose to lay it without cutting should be a factor of 9 and 12 both.
As we know, 1 is a factor of all the numbers, so he can buy tiles of measure 1 foot × 1 foot.
Now, 2 is not a factor of 9, so tiles of measure 2 foot × 2 foot cannot be laid without cutting.
Also, we know 3 is a factor of 9 and 12 both, so he can also choose the tiles of measure
3 feet × 3 feet.
Thus, he can buy tiles with measure 1 foot × 1 foot or 3 feet × 3 feet for his room.
Rani, Geetha and Naseema live near each other. The distance from their houses to the road is 90 feet. They decided to tile the path to the road. They all bought tiles of different designs and length. Rani bought the shortest tile, Geetha bought the middle sized one and Naseema bought the longest one. If they could tile the path without cutting any of the tiles, what is the size of the tiles each has bought? Suggest 3 different solutions. Explain how you get this answer.
Length of the path = 90 feet
Now, they have to choose a size of tile that can be tiled on the path without cutting.
So, size of tile should be a factor of 90.
Factors of 90 are 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45 and 90.
Rani chooses the smallest size tile, Geetha takes the middle sized and Naseema the largest.
So, we can choose the tiles in the following way:
(a) Rani can take tiles of size 1 foot 1 foot, Geetha can choose tiles of size 2 feet 2 feet, Naseema can buy tiles of size 3 feet 3 feet.
(b)Rani can take tiles of size 2 feet 2 feet, Geetha can choose tiles of size 3 feet 3 feet, Naseema can buy tiles of size 5 feet 5 feet.
(c) Rani can take tiles of size 3 feet 3 feet, Geetha can choose tiles of size 5 feet 5 feet, Naseema can buy tiles of size 6 feet 6 feet.