Mathematics Part ii Solutions Solutions for Class 10 Math Chapter 5 Statistics are provided here with simple stepbystep explanations. These solutions for Statistics are extremely popular among class 10 students for Math Statistics Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part ii Solutions Book of class 10 Math Chapter 5 are provided here for you for free. You will also love the adfree experience on Meritnationâ€™s Mathematics Part ii Solutions Solutions. All Mathematics Part ii Solutions Solutions for class 10 Math are prepared by experts and are 100% accurate.
Page No 193:
Question 1:
The table below classifies the number of days of a month according to the amount of rainfall received in a certain locality.
Find the mean daily rainfall during this month.
Rainfall (mm) 
Number of days 

54 56 58 55 50 47 44 41 
3 5 6 3 2 4 5 2 
Answer:
We can make the complete table as follows:
Rainfall (mm) 
Number of Days 
Total Rainfall (mm) 

54 
3 
162 

56 
5 
280 

58 
6 
348 

55 
3 
165 

50 
2 
100 

47 
4 
188 

44 
5 
220 

41 
2 
82 

Total 
30 
1545 
Mean daily rainfall =
Page No 194:
Question 1:
The table below classifies the members of a committee according to their ages.
Age 
Number of Members 

25 − 30 30 − 35 35 − 40 40 − 45 45 − 50 50 − 55 55 − 60 
6 14 16 22 5 4 3 
Calculate the mean age of the members of this committee.
Answer:
We can make the complete table as follows:
Age 
Number of Member 
Class Average 
Total Age 

25 − 30 
6 
27.5 
165 

30 − 35 
14 
32.5 
455 

35 − 40 
16 
37.5 
600 

40 − 45 
22 
42.5 
935 

45 − 50 
5 
47.5 
237.5 

50 − 55 
4 
52.5 
210 

55 − 60 
3 
57.5 
172.5 

Total 
70 

2775 
Mean age of the members of the committee =
Page No 194:
Question 2:
The table below shows the number of students in class 10 of a school, classified according to their heights:
Height (cm) 
Number of Students 

120 − 125 125 − 130 130 − 135 135 − 140 140 − 145 145 − 150 150 − 155 155 − 160 
19 36 23 23 43 21 23 12 
Calculate the mean height
Answer:
We can make the complete table as follows:
Height (cm) 
Number of Student 
Class Average 
Total Height 

120 − 125 
19 
122.5 
2327.5 

125 − 130 
36 
127.5 
4590.0 

130 − 135 
23 
132.5 
3047.5 

135 − 140 
23 
137.5 
3162.5 

140 − 145 
43 
142.5 
6127.5 

145 − 150 
21 
147.5 
3097.5 

150 − 155 
23 
152.5 
3507.5 

155 − 160 
12 
157.5 
1890.0 

Total 
200 

27750 
Mean height =
Page No 199:
Question 1:
The table below classifies according to weight, the infants born during a week in a hospital:
Weight (kg) 
Number of Infants 

2,500 2,600 2,750 2,800 3,000 3,150 3,250 3,300 3,500 
4 6 8 10 12 10 8 7 5 
Find the median weight.
Answer:
The given data can be shown as:
Weight (kg) 
Number of Infant 

Up to 2.500 
4 

Up to 2.600 
10 

Up to 2.750 
18 

Up to 2.800 
28 

Up to 3.000 
40 

Up to 3.150 
50 

Up to 3.250 
58 

Up to 3.300 
65 

Up to 3.500 
70 
Here, we need to find the weight of _{ }infant.
From the table it can be inferred that the weight of the 29^{th} infant to the 40^{th} infant is 3.000 kg.
So, the weight of the 35^{th} infant is 3.000 kg.
Thus, the median weight of the infants born during the week in the hospital is 3.000 kg.
Page No 200:
Question 1:
The table below shows the number of employees of an office, classified according to the incometax paid by them.
Income Tax (Rupees) 
Number of Employees 

1000 − 2000 2000 − 3000 3000 − 4000 4000 − 5000 5000 − 6000 6000 − 7000 7000 − 8000 8000 − 9000 
8 10 15 18 22 8 6 3 
Compute the median incometax.
Answer:
The given data can be shown as:
Income Tax (Rupees) 
Number of Employee 

Below 2000 
8 

Below 3000 
18 

Below 4000 
33 

Below 5000 
51 

Below 6000 
73 

Below 7000 
81 

Below 8000 
87 

Below 9000 
90 
Let us tabulate the numbers 2000, 3000, … in the first row and 8, 18, … in the second row.
x 
2000 
3000 
4000 
5000 
6000 
7000 
8000 
9000 

y 
8 
18 
33 
51 
73 
81 
87 
90 
We know that the change in y is proportional to the corresponding change in x.
We have to find that value of x for which y =
_{The number 45 is between the numbers y = 33 and y = 51.}
_{The corresponding numbers are x = 4000 and x = 5000.}
_{Thus, we must have:}
Thus, the median income tax of the employees of the office is Rs.4666.67.
Page No 200:
Question 2:
The table below classifies the candidates who took and examination, according to the marks scored by them:
Marks 
Number of Candidates 

0 − 10 10 − 20 20 − 30 30 − 40 40 − 50 50 − 60 60 − 70 70 − 80 80 − 90 90 − 100 
44 40 35 20 12 10 8 6 4 1 
Find the median mark.
Answer:
Given data can be shown as:
Marks 
Number of candidate 

Below 10 
44 

Below 20 
84 

Below 30 
119 

Below 40 
139 

Below 50 
151 

Below 60 
161 

Below 70 
169 

Below 80 
175 

Below 90 
179 

Below 100 
180 
Let us tabulate the numbers 10, 20, … in the first row and 44, 84, … in the second row.
x 
10 
20 
30 
40 
50 
60 
70 
80 
90 
100 

y 
44 
84 
119 
139 
151 
161 
169 
175 
179 
180 
We know that the change in y is proportional to the corresponding change in x.
We have to find that value of x for which y =
_{The number 90 is between the numbers y = 84 and y = 119.}
_{The corresponding numbers are x = 20 and x = 30.}
_{Thus, we must have:}
Thus, the median marks of the candidates who took an examination is 21.71.
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