The expression p(x) = 2x3+ax2-bx-2 leaves the remainder 7 when divided by (2x-3) and (x+2) is a factor of the expression . calculate the values of a and b ? ( need the stept too ! ) :)

Check whether first is a factor of second .

x+1 , x3 -1

we will get ax3 + (b+a)x2 + (c+b)x + (c+d) and after this step how we are getting the value of 'a' as 1 , 'b' as -1 and 'c' as 1

Given the polynomial p(x)= x3-11x2+17x-6 . If p(x)= (x-2) q(x) + r , Then what is the valur of r and q(x) . Write p(x) as the products of three first degree polynomials .

ap is 2,4,6....find cd?

Urgent...:'( ..Equation of getting one solution , two solution and no solution ( 3 examples each ) .

Benny factorised a second degree polynomial ang got (x+2) , (x-3) as factors. But later he found that he was mistakenly taken the opposite sign of coefficient of x . What are the factors of the actual polynomial ?

• 5. When p(x)is divided by (ax + b), the quotient is q(x)and the remainder is c
• p(x) = (ax + b)×q(x) + c
• When does the value of p(x)equal to c p(−b a ) = (a× −b a + b)×q(−b a ) + c
• What is the remainder when p(x)is divided by ax + b
• When does (ax + b)become the factor of p(x)

•  2. Expand (x−a)(x−b)
• If x2 -7x + 12 = (x−a)(x−b)then find a + b. Also find ab
• Calculate the values of a,b
• Write the factors of (x2 −7x + 12 )
• Find the solutions of (x2 −7x + 12)
• plss answer fastt