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The expression p(x) = 2x3+ax2-bx-2 leaves the remainder 7 when divided by (2x-3) and (x+2) is a factor of the expression . calculate the values of a and b ? ( need the stept too ! ) :)

Check whether first is a factor of second .

x+1 , x3 -1

we will get ax3 + (b+a)x2 + (c+b)x + (c+d) and after this step how we are getting the value of 'a' as 1 , 'b' as -1 and 'c' as 1

^{2}+bx+c=0,given 2x-3 is a factor of the polynomial ax^{2}+bx+cGiven the polynomial p(x)= x3-11x2+17x-6 . If p(x)= (x-2) q(x) + r , Then what is the valur of r and q(x) . Write p(x) as the products of three first degree polynomials .

ap is 2,4,6....find cd?

. If p(x) = (x−1)× q(x)then ﬁnd q(x).

Write q(x)as the product of two ﬁrst degree polynomials

plss answer fastt

Urgent...:'( ..Equation of getting one solution , two solution and no solution ( 3 examples each ) .

Benny factorised a second degree polynomial ang got (x+2) , (x-3) as factors. But later he found that he was mistakenly taken the opposite sign of coefficient of x . What are the factors of the actual polynomial ?

^{3}-11 x^{2}+13 x-8 to get a polynomial having (x-2) and (x-3) as factors?write a third-degree polynomial with (x^2-9) as its factor

^{50}−1a) Prove that (x - 2) is a factor of p (x)

b) Prove that for any number x, p (x) is always non negative

c) Find the number a and b such that p(a) = p (b)

Find p(x)−p(1),p(x)−p(2),p(x)−p(3) .

Write the solutions of p(x)−p(1) = 0

plss answwr fastt..urgent

b) What first degree polynomial should be added to 2x ^3 - 4x ^2 for (x^ 2 - 4) to be its factor

plss answer b part of the question

please explain the steps to solve