Mathematics Part I Solutions Solutions for Class 6 Math Chapter 5 Volume are provided here with simple step-by-step explanations. These solutions for Volume are extremely popular among Class 6 students for Math Volume Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part I Solutions Book of Class 6 Math Chapter 5 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Part I Solutions Solutions. All Mathematics Part I Solutions Solutions for class Class 6 Math are prepared by experts and are 100% accurate.

#### Question 1:

The length, breadth and height of a rectangular iron block are 8 centimetres, 5 centimetres and 2 centimetres. What is its volume?

The weight of 1 cubic centimeter of iron is 7.8 grams. What is the weight of the iron block?

Length of the rectangular iron block = 8 cm

Breadth of the rectangular iron block = 5 cm

Height of the rectangular iron block = 2 cm

Volume of the rectangular iron block = Length × Breadth × Height

= 8 cm × 5 cm × 2 cm

= 80 cm3

Weight of 1 cm3 of iron = 7.8 g

Weight of 80 cm3 of iron = 7.8 × 80 g = 624 g

Thus, the weight of the iron block is 624 g.

#### Question 2:

Ramesan bought a wooden plank to make a table. It is 120 centimetres long, 80 centimetres broad and 2 centimetres thick. What is its volume? The price of the plank is 760 rupees. What is the price of 1 cubic centimetres of wood?

Length of the rectangular wooden plank = 120 cm

Breadth of the rectangular wooden plank = 80 cm

Height of the rectangular wooden plank = 2 cm

Volume of the rectangular wooden plank = Length × Breadth × Height

= 120 cm × 80 cm × 2 cm

= 19200 cm3

Price of the wooden plank = Rs.760

Price of 19200 cm3 of wood = Rs.760

Price of 1 cm3 of wood = Rs. = Rs.0.0396

#### Question 1:

The table below lists the measurements of certain rectangular blocks. Can you find out the missing measurements? The measurements are all in centimetres.

 Length (cm) Breadth (cm) Height (cm) Volume (cu.cm) 1. 40 …… 30 600 2. …... 15 16 6000 3. 12 5 …… 90 4. 6 …… 4 12 5. 16 2 1 ……

1. Length of the rectangular block = 40 cm

Height of the rectangular block = 30 cm

Volume of the rectangular block = 600 cm3

Volume of the rectangular block = Length × Breadth × Height

2. Breadth of the rectangular block = 15 cm

Height of the rectangular block = 16 cm

Volume of the rectangular block = 6000 cm3

Volume of the rectangular block = Length × Breadth × Height

3. Length of the rectangular block = 12 cm

Breadth of the rectangular block = 5 cm

Volume of the rectangular block = 90 cm3

Volume of the rectangular block = Length × Breadth × Height

4. Length of the rectangular block = 6 cm

Height of the rectangular block = 4 cm

Volume of the rectangular block = 12 cm3

Volume of the rectangular block = Length × Breadth × Height

5. Length of the rectangular block = 16 cm

Breadth of the rectangular block = 2 cm

Height of the rectangular block = 1 cm

Volume of the rectangular block = Length × Breadth × Height

= 16 cm × 2 cm × 1 cm

= 32 cm3

The table can be completed as follows:

 Length (cm) Breadth (cm) Height (cm) Volume (cu.cm) 1 40 0.5 30 600 2 25 15 16 6000 3 12 5 1.5 90 4 6 0.5 4 12 5 16 2 1

#### Question 1:

Jose is constructing a house. He dug a pit in the ground in the shape of a rectangular block and laid plastic shut in it to collect water. The internal length, breadth and height of the pit are 2 metre, 1 metre and 80 centimetre. Find the amount of water that the pit holds.

Length of the pit = 2 m = 2 × 100 cm = 200 cm

Breadth of the pit = 1 m = 1 × 100 cm = 100 cm

Height of the pit = 80 cm

Volume of the pit = Length × Breadth × Height

= 200 cm × 100 cm × 80 cm

= 1600000 cm3

= (1 litre = 1000 cu. cm)

= 1600 litres

Therefore, the pit can hold 1600 litres of water.

#### Question 2:

Thankamma has a water tank on the roof of her house. Its internal length is metres and breadth 1 metre. Thankamma says it will hold 1050 litres of water. What is its height?

Length of the tank =

Breadth of the tank = 1 m = 100 cm

Capacity of tank = 1050 litres

Volume of the tank = 1050 liters = 1050 × 1000 cm3 (1 litre = 1000 cu. cm)

Volume of the tank = Length × Breadth × Height

#### Question 1:

A mysorepak in venus bakery is of length 6 centimetres, breadth 4 centimetres and height 2 centimetres. The price of each is 4 rupees. When demand increased, the dimensions were all halved as was the price. Appu went to buy a mysorepak. He exclaimed: You should reduce the price to 50 paise!

Is Appu right? Check it out.

Initial length of the mysorepak = 6 cm

Initial breadth of the mysorepak = 4 cm

Initial height of the mysorepak = 2 cm

Initial volume of the mysorepak = Length × Breadth × Height

= 6 cm × 4 cm × 2 cm

= 48 cm3

New dimensions of mysorepak due to increase in price = Half of the initial dimensions

New length of the mysorepak =3 cm

New breadth of the mysorepak =2 cm

New height of the mysorepak = 1 cm

New volume of the mysorepak = Length × Breadth × Height

= 3 cm × 2 cm × 1 cm

= 6 cm3

Initial price of the mysorepak = Rs.4

New price of the mysorepak as fixed by the shopkeeper =Initial price of the mysorepak

= Rs.2

Price of the mysorepak according to Appu = Rs.0.5

Ratio of price = New price : Initial price = 0.5 : 4 = 1 : 8

Ratio of volumes = New volume : Initial volume = 6 : 48 = 1 : 8

According to Appu, price must be reduced in the ratio of volume.

Yes, Appu is absolutely right.

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