Mathematics Part I Solutions Solutions for Class 6 Math Chapter 5 Volume are provided here with simple step-by-step explanations. These solutions for Volume are extremely popular among Class 6 students for Math Volume Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part I Solutions Book of Class 6 Math Chapter 5 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Part I Solutions Solutions. All Mathematics Part I Solutions Solutions for class Class 6 Math are prepared by experts and are 100% accurate.
Page No 75:
Question 1:
The length, breadth and height of a rectangular iron block are 8 centimetres, 5 centimetres and 2 centimetres. What is its volume?
The weight of 1 cubic centimeter of iron is 7.8 grams. What is the weight of the iron block?
Answer:
Length of the rectangular iron block = 8 cm
Breadth of the rectangular iron block = 5 cm
Height of the rectangular iron block = 2 cm
Volume of the rectangular iron block = Length × Breadth × Height
= 8 cm × 5 cm × 2 cm
= 80 cm^{3}
Weight of 1 cm^{3} of iron = 7.8 g
∴ Weight of 80 cm^{3} of iron = 7.8 × 80 g = 624 g
Thus, the weight of the iron block is 624 g.
Page No 75:
Question 2:
Ramesan bought a wooden plank to make a table. It is 120 centimetres long, 80 centimetres broad and 2 centimetres thick. What is its volume? The price of the plank is 760 rupees. What is the price of 1 cubic centimetres of wood?
Answer:
Length of the rectangular wooden plank = 120 cm
Breadth of the rectangular wooden plank = 80 cm
Height of the rectangular wooden plank = 2 cm
Volume of the rectangular wooden plank = Length × Breadth × Height
= 120 cm × 80 cm × 2 cm
= 19200 cm^{3}
Price of the wooden plank = Rs.760
∴ Price of 19200 cm^{3} of wood = Rs.760
∴ Price of 1 cm^{3} of wood = Rs. = Rs.0.0396
Page No 76:
Question 1:
The table below lists the measurements of certain rectangular blocks. Can you find out the missing measurements? The measurements are all in centimetres.
Length (cm) |
Breadth (cm) |
Height (cm) |
Volume (cu.cm) |
||||||
1. |
40 |
…… |
30 |
600 |
|||||
2. |
…... |
15 |
16 |
6000 |
|||||
3. |
12 |
5 |
…… |
90 |
|||||
4. |
6 |
…… |
4 |
12 |
|||||
5. |
16 |
2 |
1 |
…… |
Answer:
1. Length of the rectangular block = 40 cm
Height of the rectangular block = 30 cm
Volume of the rectangular block = 600 cm^{3}
Volume of the rectangular block = Length × Breadth × Height
2. Breadth of the rectangular block = 15 cm
Height of the rectangular block = 16 cm
Volume of the rectangular block = 6000 cm^{3}
Volume of the rectangular block = Length × Breadth × Height
3. Length of the rectangular block = 12 cm
Breadth of the rectangular block = 5 cm
Volume of the rectangular block = 90 cm^{3}
Volume of the rectangular block = Length × Breadth × Height
4. Length of the rectangular block = 6 cm
Height of the rectangular block = 4 cm
Volume of the rectangular block = 12 cm^{3}
Volume of the rectangular block = Length × Breadth × Height
5. Length of the rectangular block = 16 cm
Breadth of the rectangular block = 2 cm
Height of the rectangular block = 1 cm
Volume of the rectangular block = Length × Breadth × Height
= 16 cm × 2 cm × 1 cm
= 32 cm^{3}
The table can be completed as follows:
Length (cm) |
Breadth (cm) |
Height (cm) |
Volume (cu.cm) |
||||||
1 |
40 |
0.5 |
30 |
600 |
|||||
2 |
25 |
15 |
16 |
6000 |
|||||
3 |
12 |
5 |
1.5 |
90 |
|||||
4 |
6 |
0.5 |
4 |
12 |
|||||
5 |
16 |
2 |
1 |
Page No 78:
Question 1:
Jose is constructing a house. He dug a pit in the ground in the shape of a rectangular block and laid plastic shut in it to collect water. The internal length, breadth and height of the pit are 2 metre, 1 metre and 80 centimetre. Find the amount of water that the pit holds.
Answer:
Length of the pit = 2 m = 2 × 100 cm = 200 cm
Breadth of the pit = 1 m = 1 × 100 cm = 100 cm
Height of the pit = 80 cm
Volume of the pit = Length × Breadth × Height
= 200 cm × 100 cm × 80 cm
= 1600000 cm^{3}
= (1 litre = 1000 cu. cm)
= 1600 litres
Therefore, the pit can hold 1600 litres of water.
Page No 78:
Question 2:
Thankamma has a water tank on the roof of her house. Its internal length is metres and breadth 1 metre. Thankamma says it will hold 1050 litres of water. What is its height?
Answer:
Length of the tank =
Breadth of the tank = 1 m = 100 cm
Capacity of tank = 1050 litres
∴ Volume of the tank = 1050 liters = 1050 × 1000 cm^{3 }(1 litre = 1000 cu. cm)
Volume of the tank = Length × Breadth × Height
Page No 79:
Question 1:
A mysorepak in venus bakery is of length 6 centimetres, breadth 4 centimetres and height 2 centimetres. The price of each is 4 rupees. When demand increased, the dimensions were all halved as was the price. Appu went to buy a mysorepak. He exclaimed: You should reduce the price to 50 paise!
Is Appu right? Check it out.
Answer:
Initial length of the mysorepak = 6 cm
Initial breadth of the mysorepak = 4 cm
Initial height of the mysorepak = 2 cm
Initial volume of the mysorepak = Length × Breadth × Height
= 6 cm × 4 cm × 2 cm
= 48 cm^{3}
New dimensions of mysorepak due to increase in price = Half of the initial dimensions
∴ New length of the mysorepak =3 cm
New breadth of the mysorepak =2 cm
New height of the mysorepak = 1 cm
New volume of the mysorepak = Length × Breadth × Height
= 3 cm × 2 cm × 1 cm
= 6 cm^{3}
Initial price of the mysorepak = Rs.4
New price of the mysorepak as fixed by the shopkeeper =Initial price of the mysorepak
= Rs.2
Price of the mysorepak according to Appu = Rs.0.5
Ratio of price = New price : Initial price = 0.5 : 4 = 1 : 8
Ratio of volumes = New volume : Initial volume = 6 : 48 = 1 : 8
According to Appu, price must be reduced in the ratio of volume.
Yes, Appu is absolutely right.
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