Mathematics Part i Solutions Solutions for Class 7 Math Chapter 5 Math Drawing are provided here with simple step-by-step explanations. These solutions for Math Drawing are extremely popular among class 7 students for Math Math Drawing Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part i Solutions Book of class 7 Math Chapter 5 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Part i Solutions Solutions. All Mathematics Part i Solutions Solutions for class 7 Math are prepared by experts and are 100% accurate.

Page No 57:

Question 1:

Draw an equilateral triangle of side 6 centimeters in your notebook.

 

Answer:

The steps for construction of the required triangle are as follows.

1. Draw a circle with centre P and radius 6 cm. Also, join the centre P with a point on the circle, say, Q.

2. Take Q as the centre and draw a circle of same radius, which intersects the first circle at point R.

3. Join PR and RQ.

Thus, ΔPQR is the required equilateral triangle.



Page No 58:

Question 1:

Draw triangles with sides as given below.

AB = 5 cm, BC = 7 cm, CA = 8 cm

 

Answer:

The steps for construction of the required triangle are as follows.

1. Draw a line segment AB of length 5 cm.

2. Take A as the centre and 8 cm as the radius to draw part of a circle.

3. Take B as the centre and 7 cm as the radius to draw part of a circle.

4. Mark a point C where these parts of circles intersect.

5. Join AC and CB.

Thus, ΔABC is the required triangle.

Page No 58:

Question 2:

Draw triangles with sides as given below.

PQ = 3 cm, QR = 4 cm, RP = 5 cm

 

Answer:

The steps for construction of the required triangle are as follows.

1. Draw a line segment PQ of length 3 cm.

2. Take P as the centre and 5 cm as the radius to draw part of a circle.

3. Take Q as the centre and 4 cm as the radius to draw part of a circle.

4. Mark a point R where these parts of circles intersect.

5. Join RP and RQ.

Thus, ΔPQR is the required triangle.

 

Page No 58:

Question 3:

Draw triangles with sides as given below.

XY = 5 cm, YZ = 4 cm, XZ = 4 cm

 

Answer:

The steps for construction of the required triangle are as follows.

1. Draw a line segment XY of length 5 cm.

2. Take X as the centre and 4 cm as the radius to draw part of a circle.

3. Take Y as the centre and 4 cm as the radius to draw part of a circle.

4. Mark a point Z where these parts of circles intersect.

5. Join XZ and YZ.

Thus, ΔXYZ is the required triangle.

 

Page No 58:

Question 4:

Draw triangles with sides as given below.

DE = 3.5 cm, EF = 4.5 cm, FD = 5.5 cm

Answer:

The steps for construction of the required triangle are as follows:

1. Draw a line segment DE of length 3.5 cm.

2. Take D as the centre and 5.5 cm as the radius to draw part of a circle.

3. Take E as the centre and 4.5 cm as the radius to draw part of a circle.

4. Mark a point F where these parts of circles intersect.

5. Join FD and EF.

Thus, ΔDEF is the required triangle.



Page No 60:

Question 1:

Suppose we want to draw a triangle with one side 6 centimeters long. Which of the following pairs of lengths can be the lengths of the other two sides?

(i) 4 cm, 1 cm

(ii) 4 cm, 2 cm

(iii) 4 cm, 3 cm

(iv) 5 cm, 10 cm

(v) 5 cm, 11 cm

(vi) 5 cm, 12 cm

 

Answer:

(i) To check whether we can construct a triangle with the given measurements or not, we need to do the following constructions.

Step 1: Draw a line segment AB of length 6 cm.

Step 2: Draw two circles of radii 4 cm and 1 cm centred at A and B, respectively.

We can observe that the circles do not intersect each other, so 6 cm, 4 cm and 1 cm are not the lengths of the sides of the required triangle.

(ii) To check whether we can construct a triangle with the given measurements or not, we need to do the following constructions.

Step 1: Draw a line segment AB of length 6 cm.

Step 2: Draw two circles of radii 4 cm and 2 cm centred at A and B, respectively.

We can observe that the circles do not intersect each other, so 6 cm, 4 cm and 2 cm are not the lengths of the sides of the required triangle.

(iii) To check whether we can construct a triangle with the given measurements or not, we need to do the following constructions.

Step 1: Draw a line segment AB of length 6 cm.

Step 2: Draw two circles of radii 4 cm and 3 cm centred at A and B, respectively.

We can observe that the circles intersect each other at a point, say, C.

Step 3: Join AC and BC.

Thus, 6 cm, 4 cm and 3 cm are the lengths of the sides of the required triangle ABC.

(iv) To check whether we can construct a triangle with the given measurements or not, we need to do the following constructions.

Step 1: Draw a line segment AB of length 6 cm.

Step 2: Draw two circles of radii 5 cm and 10 cm centred at A and B, respectively.

We can observe that the circles intersect each other at point C.

Step 3: Join AC and BC.

Thus, 6 cm, 5 cm and 10 cm are the lengths of the sides of the required triangle ABC.

(v) To check whether we can construct a triangle with the given measurements or not, we need to do the following constructions.

Step 1: Draw a line segment AB of length 6 cm.

Step 2: Draw two circles of radii 5 cm and 11 cm centred at A and B, respectively.

We can observe that the circles do not intersect each other, so 6 cm, 5 cm and 11 cm are not the lengths of the sides of the required triangle.

(vi) To check whether we can construct a triangle with the given measurements or not, we need to do the following constructions.

Step 1: Draw a line segment AB of length 6 cm.

Step 2: Draw two circles of radii 5 cm and 12 cm centred at A and B, respectively.

We can observe that the circles do not intersect each other, so 6 cm, 5 cm and 12 cm are not the lengths of the sides of the required triangle.



Page No 62:

Question 1:

Try to draw triangles with measurements as given below.

(i) AB = 5 cm, AC = 6 cm, A = 60°

(ii) PQ = 4.5 cm, QR = 5 cm, Q = 65°

(iii) XY = 7 cm, XZ = 5 cm, X = 100°

(iv) CD = 5 cm, CE = 5 cm, C = 40°

(v) LM = 4 cm, MN = 4 cm, L = 60°

 

Answer:

(i) The steps for construction of the required triangle are as follows.

1. Draw a line segment AB of length 5 cm.

2. Draw a line segment through point A, making an angle of 60° with AB.

3. Mark a point C at a distance of 6 cm from point A on the line segment drawn in the previous step.

4. Join BC.

Thus, ΔABC is the required triangle.

(ii) The steps for construction of the required triangle are as follows.

1. Draw a line segment PQ of length 4.5 cm.

2. Draw a line segment through the point Q, making an angle of 65° with PQ.

3. Mark a point R at a distance of 5 cm from Q on the line segment drawn in the previous step.

4. Join PR.

Thus, ΔPQR is the required triangle.

(iii) The steps for construction of the required triangle are as follows.

1. Draw a line segment XY of length 7 cm.

2. Draw a line segment through point X, making an angle of 100° with XY.

3. Mark a point Z at a distance of 5 cm from X on the line segment drawn in the previous step.

4. Join ZY.

Thus, ΔXYZ is the required triangle.

(iv) The steps for construction of the required triangle are as follows.

1. Draw a line segment CD of length 5 cm.

2. Draw a line through the point C, making an angle of 40° with CD.

3. Mark a point E at a distance of 5 cm from C on the line segment drawn in the previous step.

4. Join DE.

Thus, ΔCDE is the required triangle.

(v) The steps for construction oft the required triangle are as follows.

1. Draw a line segment LM of length 4 cm.

2. Draw a line segment through point L, making an angle of 60° with LM.

3. Draw part of a circle centred at M and of radius 4 cm on the line segment drawn in the previous step. Mark the point of intersection as N.

4. Join MN.

Thus, ΔLMN is the required triangle.



Page No 67:

Question 1:

Draw triangles of the following measurements.

(i) ΔPQR : PQ = 5 cm, P = 65°, Q = 65°

(ii) ΔABC : AB = 6 cm, A = 40°, B = 40°

(iii) ΔLMN : LM = 4 cm, L = 90°, M = 30°

(iv) ΔXYZ : XY = 5 cm, X = 90°, Q = 45°

 

Answer:

(i) The steps for construction of the required triangle are as follows.

1. Draw a line segment PQ of length 5 cm.

2. Draw a line segment through point P, making an angle of 65° with PQ.

3. Draw a line segment through point Q, making an angle of 65° with PQ. Mark the point of intersection as R.

Thus, ΔPQR is the required triangle.

(ii) The steps for construction of the required triangle are as follows.

1. Draw a line segment AB of length 6 cm.

2. Draw a line segment through point A, making an angle of 40° with AB.

3. Draw a line segment through point B, making an angle of 40° with AB. Mark the point of intersection as C.

Thus, ΔABC is the required triangle.

(iii) The steps for construction of the required triangle are as follows.

1. Draw a line segment LM of length 4 cm.

2. Draw a line segment through point L, making an angle of 90° with LM.

3. Draw a line segment through point M, making an angle of 30° with LM. Mark the point of intersection as N.

Thus, ΔLMN is the required triangle.

(iv) The steps for construction of the required triangle are as follows.

1. Draw a line segment XY of length 5 cm.

2. Draw a line segment through point X, making an angle of 90° with XY.

3. Draw a line segment through point Y, making an angle of 45° with XY. Mark the point of intersection as Z.

Thus, ΔXYZ is the required triangle.



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