Mathematics Part ii Solutions Solutions for Class 7 Math Chapter 6 Negative Numbers are provided here with simple step-by-step explanations. These solutions for Negative Numbers are extremely popular among class 7 students for Math Negative Numbers Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part ii Solutions Book of class 7 Math Chapter 6 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Part ii Solutions Solutions. All Mathematics Part ii Solutions Solutions for class 7 Math are prepared by experts and are 100% accurate.
Page No 156:
Question 1:
The table shows the number of cards some kids got.
Can you find out their scores?
|
White Card |
Black Card |
Score |
|
|
Jaya |
7 |
3 |
|
|
Manu |
10 |
0 |
|
|
Sushama |
4 |
6 |
|
|
Kuttan |
3 |
7 |
|
|
Abu |
8 |
2 |
|
|
John |
5 |
5 |
|
|
Nazeema |
2 |
8 |
Answer:
According to the card game, the score is the number of white cards less the number of black cards.
|
White card |
Black card |
Score |
|
|
Jaya |
7 |
3 |
7 − 3 = 4 |
|
Manu |
10 |
0 |
10 − 0 = 10 |
|
Sushama |
4 |
6 |
4 − 6 = −2 |
|
Kuttan |
3 |
7 |
3 − 7 = −4 |
|
Abu |
8 |
2 |
8 − 2 = 6 |
|
John |
5 |
5 |
5 − 5 = 0 |
|
Nazaama |
2 |
8 |
2 − 8 = −6 |
Page No 156:
Question 2:
Can you now do these?
(i) 4 − 7
(ii) 3 − 9
(iii) 6 − 10
(iv) 2 − 12
(v) 4 − 12
Answer:
(i) 4 − 7 = −3
(ii) 3 − 9 = −6
(iii) 6 − 10 = −4
(iv) 2 − 12 = −10
(v) 4 − 12 = −8
Page No 157:
Question 1:
Now complete this table.
|
(i) 8 − 7 |
= |
...... |
(ii) 7 − 8 |
= |
...... |
|
|
(iii) 9 − 5 |
= |
...... |
(iv) 5 − 9 |
= |
...... |
|
|
(v) 8 − 4 |
= |
...... |
(vi) 4 − 8 |
= |
...... |
|
|
(vii) 9 − 3 |
= |
...... |
(viii) 3 − 9 |
= |
...... |
Answer:
|
(i) 8 − 7 = 1 (iii) 9 − 5 = 4 (v) 8 − 4 = 4 (vii) 9 − 3 = 6 |
(ii) 7 − 8 = −1 (iv) 5 − 9 = −4 (vi) 4 − 8 = −4 (viii) 3 − 9 = −6 |
Page No 157:
Question 2:
Now, can’t you compute these differences?
(i) 128 − 176
(ii) 248 − 312
(iii) 
Answer:
We know that for any two positive numbers x and y, with x < y, we have x − y = −(y − x)
(i) 128 − 176 = −(176 − 128) = −48
(ii) 248 − 312 = −(312 − 248) = −64
(iii) = =
Page No 159:
Question 1:
Now can’t you do these?
(i) −4 + 7
(ii) −3 + 8
(iii) −6 + 9
(iv) −2 + 10
(v) −4 + 12
(vi)
Answer:
(i) −4 + 7 = 7 − 4 = 3
(ii) −3 + 8 = 8 − 3 = 5
(iii) −6 + 9 = 9 − 6 = 3
(iv) −2 + 10 = 10 − 2 = 8
(v) −4 + 12 = 12 − 4 = 8
(vi)
Page No 159:
Question 2:
Now compute these.
(i) −4 + 1
(ii) −5 + 3
(iii) −9 + 2
(iv) −12 + 8
(v) −14 + 1
(vi)
Answer:
(i) −4 + 1 = 1 − 4 = −3
(ii) −5 + 3 = 3 − 5 = −2
(iii) −9 + 2 = 2 − 9 = −7
(iv) −12 + 8 = 8 − 12 = −4
(v) −14 + 1 = 1 − 14 = −13
(vi)
Page No 160:
Question 1:
Now do these also:
(i) 3 + (−1)
(ii) 5 + (−4)
(iii)12 + (−2)
(iv) 8 + (−9)
(v) 9 + (−12)
(vi)
Answer:
(i) 3 + (−1) = −1 + 3 = 3 − 1 = 2
(ii) 5 + (−4) = −4 + 5 = 5 − 4 = 1
(iii) 12 + (−2) = −2 + 12 = 12 − 2 = 10
(iv) 8 + (−9) = −9 + 8 = 8 − 9 = −1
(v) 9 + (− 12) = −12 + 9 = 9 − 12 = −3
(vi)
Page No 161:
Question 1:
Now can’t you do these?
(i) −3 −1
(ii) −5 −6
(iii) −8 −8
(iv) −12 −18
(v)
Answer:
(i) −3 − 1 = − (3 + 1) = −4
(ii) −5 − 6 = − (5 + 6) = −11
(iii) −8 − 8 = − (8 + 8) = −16
(iv) −12 − 18 = − (12 + 18) = −30
(v)
Page No 162:
Question 1:
Now can’t you do these?
(i) −4 + (−1)
(ii) −6 + (−4)
(iii) −12 + (−8)
(iv) −8 + (−10)
(v)
Answer:
We know that for any two positive numbers x, y, we have − x − y = − (x + y)
(i) −4 + (−1) = −4 −1
= − (4 + 1)
= −5
(ii) −6 + (−4) = −6 − 4
= − (6 + 4)
= −10
(iii) −12 + (−8) = −12 − 8
= − (12 + 8)
= −20
(iv) −8 + (−10) = −8 − 10
= − (8 + 10)
= −18
(v)
Page No 162:
Question 2:
What number is to be added to 5, to get 13?
Answer:
The number to be added to 5 to get 13 is obtained by subtracting 5 from 13.
13 − 5 = 8
So, 8 should be added to 5 to get 13.
Page No 162:
Question 3:
What number should we add to 5, to get 3?
Answer:
The number that should be added to 5 to get 3 is obtained by subtracting 5 from 3.
3 − 5 = −2
So, −2 should be added to 5 to get 3.
Page No 162:
Question 4:
What number should be add to 5, to get 0?
Answer:
The number that should be added to 5 to get 0 is obtained by subtracting 5 from 0.
0 − 5 = −5
So, −5 should be added to 5 to get 0.
Page No 162:
Question 5:
What is to be added to 5, to get −3?
Answer:
The number to be added to 5 to get −3 is obtained by subtracting 5 from −3.
−3 − 5 = −8
So, −8 should be added to 5 to get −3.
Page No 162:
Question 6:
What should we add to 5, to get −5?
Answer:
The number to be added to 5 to get −5 is obtained by subtracting 5 from −5.
−5 − 5 = −10
So, −10 should be added to 5 to get −5.
Page No 164:
Question 1:
Now can’t you easily do these?
(i) 4 − (−1)
(ii) 6 − (−2)
(iii) 12 − (−8)
(iv) 2 − (−2)
(v)
Answer:
We know that for any two positive numbers x and y, we have x − (−y) = x + y.
(i) 4 − (−1) = 4 + 1 = 5
(ii) 6 − (−2) = 6 + 2 = 8
(iii) 12 − (−8) = 12 + 8 = 20
(iv) 2 − (−2) = 2 + 2 = 4
(v) = =
Page No 165:
Question 1:
Now can’t you compute these?
(i) −4 − (−5)
(ii) −6 − (−9)
(iii) −12 − (−10)
(iv) −8 − (−7)
(v)
Answer:
We know that for any two positive numbers x and y, we have −x − (−y) = −x + y.
(i) −4 − (−5) = −4 + 5 = 5 − 4= 1
(ii) −6 − (−9) = −6 + 9 = 9 − 6 = 3
(iii) −12 − (−10) = −12 + 10 = 10 − 12 = −2
(iv) −8 − (−7) = −8 + 7 = 7 − 8 = −1
(v)
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