Mathematics Part I Solutions Solutions for Class 9 Math Chapter 2 Rational Numbers are provided here with simple step-by-step explanations. These solutions for Rational Numbers are extremely popular among Class 9 students for Math Rational Numbers Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part I Solutions Book of Class 9 Math Chapter 2 are provided here for you for free. You will also love the ad-free experience on Meritnationâ€™s Mathematics Part I Solutions Solutions. All Mathematics Part I Solutions Solutions for class Class 9 Math are prepared by experts and are 100% accurate.

#### Page No 21:

#### Question 1:

Simplify the expressions below

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

#### Answer:

(i)

(ii)

(iii)

(iv)

(v)

**= ***x *+ *y*

(vi)

**= **

(vii)

(viii)

#### Page No 23:

#### Question 1:

Can’t you do the following problem?

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

(ix)

#### Answer:

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

(ix)

#### Page No 24:

#### Question 1:

Try these problems on your own:

(i)

(ii)

(iii)

(iv)

#### Answer:

(i)

(ii)

(iii)

(iv)

#### Page No 28:

#### Question 1:

If , then what is ?

#### Answer:

We have

, i.e., the fractions are the different forms of the same number.

Let

⇒ *x* = = 3*z** *and *y* = = 4*z*

Substituting in, we get:

⇒

#### Page No 28:

#### Question 2:

Prove that if then . Will this be true if we use some other numbers instead of 2, 5, 4 and 6?

#### Answer:

We have

, i.e., the fractions are the different forms of the same number.

Let

⇒ *x* = = *uz *and *y* = = *vz*

Substituting in , we get:

⇒

Let us suppose we have numbers *a*, *b*, *c* and *d *instead of 2, 5, 4 and 6 in the given equation.

Therefore, we need to show

L.H.S. =

= R.H.S.

Hence, we can use any number instead of the numbers 2, 5, 4 and 6 for the given equation to hold true.

#### Page No 28:

#### Question 3:

Prove that if then each is equal to . Is this true for other numbers, instead of 2 and 5?

#### Answer:

We have

, i.e., the fractions are the different forms of the same number.

Let

⇒ *x* = = *uz *and *y* = = *vz*

_{As } _{, we get:}

Let us suppose we have numbers *a* and *b*, *c* and *d *instead of 2 and 5 in the given equation.

Therefore, we need to show

_{As } _{, we get:}

Hence, we can use any number instead of the numbers 2 and 5 for the given equation to hold true.

#### Page No 34:

#### Question 1:

Try writing the following fractions as decimals.

(i)

(ii)

(iii)

(iv)

(v)

(vi)

#### Answer:

(i)

The fraction can be expressed in decimals by division method as:

∴= 0.111…

(ii)

The fraction can be expressed in decimals by division method as:

∴= 0.222…

(iii)

The fraction can be expressed in decimals by division method as:

∴= 0.1428571…

(iv)

The fraction can be expressed in decimals by division method as:

∴= 0.0909….

(v)

The fraction can be expressed in decimals by division method as:

∴= 0.1818….

(vi)

The fraction can be expressed in decimals by division method as:

∴= 0.0833…

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