Mathematics Part I Solutions for Class 9 Maths Chapter 2 - Rational Numbers

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Mathematics Part I Solutions Solutions for Class 9 Maths Chapter 2 Rational Numbers are provided here with simple step-by-step explanations. These solutions for Rational Numbers are extremely popular among Class 9 students for Maths Rational Numbers Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Part I Solutions Book of Class 9 Maths Chapter 2 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Part I Solutions Solutions. All Mathematics Part I Solutions Solutions for class Class 9 Maths are prepared by experts and are 100% accurate.

Page No 21:

Question 1:

Simplify the expressions below

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

Answer:

(i)

(ii)

(iii)

(iv)

(v)

= x + y

(vi)

(vii)

(viii)

Page No 23:

Question 1:

Can’t you do the following problem?

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

(ix)

Answer:

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

(ix)

Page No 24:

Question 1:

Try these problems on your own:

(i)

(ii)

(iii)

(iv)

Answer:

(i)

(ii)

(iii)

(iv)

Page No 28:

Question 1:

If , then what is ?

Answer:

We have

, i.e., the fractions are the different forms of the same number.

Let

⇒ x = = 3z and y = = 4z

Substituting in, we get:

⇒

Page No 28:

Question 2:

Prove that if then . Will this be true if we use some other numbers instead of 2, 5, 4 and 6?

Answer:

We have

, i.e., the fractions are the different forms of the same number.

Let

⇒ x = = uz and y = = vz

Substituting in , we get:

⇒

Let us suppose we have numbers a, b, c and d instead of 2, 5, 4 and 6 in the given equation.

Therefore, we need to show

L.H.S. =

= R.H.S.

Hence, we can use any number instead of the numbers 2, 5, 4 and 6 for the given equation to hold true.

Page No 28:

Question 3:

Prove that if then each is equal to . Is this true for other numbers, instead of 2 and 5?

Answer:

We have

, i.e., the fractions are the different forms of the same number.

Let

⇒ x = = uz and y = = vz

_As _{, we get:}

Let us suppose we have numbers a and b, c and d instead of 2 and 5 in the given equation.

Therefore, we need to show

_As _{, we get:}

Hence, we can use any number instead of the numbers 2 and 5 for the given equation to hold true.

Page No 34:

Question 1:

Try writing the following fractions as decimals.

(i)

(ii)

(iii)

(iv)

(v)

(vi)