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Syllabus

If x=1+log

_{a}bc, y=1+log_{b}ac, z=1+log_{c}ab, Prove that xy+yz+zx = xyzAns: option (A).

Q.6. Four identical isosceles triangle AWB, BXC, CYD and DZE are arranged, as shown, with points A, B, C, D and E lying on the same straight line. A new triangle is formed with sides the same length as AX, AY and AZ. If AZ = AE, the area of this new triangle in terms of x is equal to

(A) $\sqrt{15}{x}^{2}$

(B) $\sqrt{5}{x}^{2}$

(C) $\sqrt{11}{x}^{2}$

(D) $\frac{15{x}^{2}}{4}$

~~ If log1227 = a, then log616 is:

log(4/3*3.14*0.87*0.87)=?

(45.83 * 0.5432)/0.02739

prove the above

find the value logof 8 to the base 1/2

2 log ( a + b ) +log ( a- b) - log ( a^{2}- b^{2}) = log x^{x}= (0.23)^{y}=1000 show that 1/x - 1/y = 1/3log(3.14*0.84*0.84*6.97)=?

how to find a square root of a given amount y using log table

^{x}= b^{y}=c^{z}and y^{2}=z x prove that log b_{a }=log_{c}b^{18}= y^{21}= z^{28}, then 3,3log_{y}^{x}, 3log_{z}^{y}, 3log_{x}^{z}are in :-1) Ap

2) Gp

3) Hp

4) AGP

Answer it soon

limit h tends to 0 a

^{h}-1 / h = log_{e}a_{5}^{(1000)}and y = log_{7}^{(2058)}are in AP :-1) x>y

2) x<y

3) x=y

4) none

log

_{2}x+ 1/2log_{2}(x+2)=2_{root a}root a{root a[root a( root a (root a ) ) ] }plsunderstand it no other way to write it

^{x+ 1}/ q^{x-1}= r^{2 x}prove that^{3}-x. b^{5 x}=a^{3 x}. b^{x+5}p

^{x+1}/q^{x-1}= r^{2x}_{8}[log_{5}( root{ x + 5 }+ root{ x } ) ] = 0{} this means the whole is under root

how to find a square roots of a given amount

Please explain in detail.

pease explain division of logariths?

Please simplify and explain!

Q). ${a}^{{\mathrm{log}}_{b}c}={c}^{{\mathrm{log}}_{b}a}$

Q.12. If n $\in $ N such that characteristic of ${n}^{2}$ to the base 8 is 2, then number of possible values of n is-

(A) 14

(B) 15

(C) 448

(D) infinite

^{log10x}- 3^{log10x -1}= 3^{log10x +1}- 5^{log10x-1 x =?}a) 2

b) 4

c) 8

d) log2*16

Answer it soon

*4. ${\left(\frac{\text{1}}{\text{3}}\right)}^{\frac{\text{|x+2|}}{\text{2-|x|}}}\text{>9}$

Asking third time :(:(

Q.10. Prove that ${a}^{x}-{b}^{y}=0$ where $x=\sqrt{{\mathrm{log}}_{a}b}y=\sqrt{{\mathrm{log}}_{b}a}$, a > 0, b > 0 & a, b $\ne $1.