Statistics (Measures of Dispersion)
Solve problems related to ranges of data sets
Let us consider the following example.
Mohit and Rohit are the opening batsmen for their school cricket team. The following table shows the runs scored by them in the last 10 innings.
Mohit 
74 
5 
55 
48 
99 
105 
30 
17 
33 
54 
Rohit 
42 
101 
51 
38 
53 
100 
105 
44 
72 
41 
Can you say who is a better batsman by observing the table?
From the given table, we observe that both of them scored a maximum of 105 runs in a match. However, this does not tell us anything.
Now, we can see that the highest runs scored by Mohit are 105, while the lowest runs scored by him are 5.
Therefore, the difference between the highest and the lowest runs scored by Mohit is
105 − 5 = 100 runs.
Hence, the range of runs scored by Mohit is 100 runs.
The difference between the highest and the lowest values of a data set is called the range of the data set. 
Similarly, the range of the runs scored by Rohit is
Highest score − Lowest score
= 105 − 38
= 67 runs
Thus, we can see that while their maximum scores were equal, the range of Rohit’s scores was lesser than the range of Mohit’s scores. What does this tell us? This tells us that Rohit was more consistent than Mohit, scoring a minimum of 38 runs in each match.
Now, let us discuss some more examples based on the above concept.
Example 1:
Find the range of the following data:
210, 150, 162, 190, 26, 175, 200, 216, 50, 127, 116, 100
Solution:
Here, highest value = 216
Lowest value = 26
The range of the given data = 216 − 26
= 190
Example 2:
The weekly temperature of Delhi is shown below.
Days 
Sunday 
Monday 
Tuesday 
Wednesday 
Thursday 
Friday 
Saturday 
Temperature (in °Celsius) 
49 
45 
40 
35 
42 
46 
48 
What is the range of temperatures?
Solution:
Here, the highest temperature is 49°C and the lowest temperature is 35°C.
Therefore, range of temperatures = Highest temperature − Lowest temperature
= 49°C − 35°C
= 14°C
 Mean deviation about the mean () of an ungrouped data x_{1}, x_{2}, x_{3} … x_{n}_{ } is given by the formula , where is the mean of x_{1}, x_{2}, x_{3} …. x_{n}. !
 
 Mean deviation about the median (M) of an ungrouped data x_{1}, x_{2}, x_{3} …. x_{n}_{ } is given by the formula, where M is the median of x_{1}, x_{2}, x_{3} …. x_{n}_{ }. !
 

To understand these concepts better, let us go through the following video.
Solved Examples
Example 1:
Find the mean deviation about the median of the following data, if its mean deviation about the mean is .
9, 17, 13, 19, 26, 31, 53, 42, x, 18, 21, 23
Where, the mean of this data lies between 23 and 26, and x lies between 27 and 31.
Solution:
To find the mean deviation about the median of the given data, first of all, we have to find the value of x.
Now, the mean of this data is given by
Since mean () of the given data lies between 23 and 26,
 For each x_{i}_{ }less than or equal to 23,
 For each x_{i}_{ }greater than or equal tâ€¦
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