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electrolyte ^

^{0m}(Sm^{2}mol^{-1})BaCl

_{2 }280x10^{-4}NaCl 126.5x10

^{-4}NaOH 248X10

^{-4 The molar conductance at infinite dilution for Ba(OH)2}is25. Which of the following solutions will have highest equivalent conductance?

a) 0.01 M NaCl b) 0.050 M NaCl c) 0.005 M NaCl d) 0.02 M NaCl

Q.72. Calculate the current (in mA) required to deposit 0.195 g of platinum metal in 5.0 hours from a solution of ${\left[PtC{l}_{6}\right]}^{2-}$: (atomic weight : Pt = 195)

(1) 310

(2) 31

(3) 21.44

(4) 5.36

The standard emf of the following cell:

Cd(s)|CdCl

_{2}(aq) (0.10 M)||Cl^{-}| AgCl(s)|Ag(s)In which the cell reaction is 2AgCl(s) + Cd(s) $\to $2Ag(s) +Cd

^{2+}+ 2Cl^{-}(aq) is 0.6915 V at 10^{0}C and 0.6753 V at 25^{0}C. The $\u2206$H of reaction at 25^{0}C is(A) -192.5 kJ (B) -234.7 kJ

(C) 123.5 kJ (D) -167.26 kJ

${\mathrm{Mn}}^{2+}+2{\mathrm{e}}^{-}\to \mathrm{Mn},\mathrm{E}\xb0=-1.18\mathrm{V}\phantom{\rule{0ex}{0ex}}{\mathrm{Mn}}^{2+}\to {\mathrm{Mn}}^{3+}+{\mathrm{e}}^{-},\mathrm{E}\xb0=-1.51\mathrm{V}$

The E° for the reaction $3{\mathrm{Mn}}^{2+}\to {\mathrm{Mn}}^{0}+2{\mathrm{Mn}}^{3+}$ and possibility of the forward reaction are respectively

(a) –4.18 V and yes (b) +0.33 V and yes

(c) +2.69 V and no (d) –2.69 V and no

Calomel electrode is an example of ?

[Given : Conductivity of 0.1 M KCl solution is 1.29 S/m]

Detailed explanation of calomel electrode

I don't understand Daniell cell plz. tell me.

what is meant by nernst?

1. 44.8 L

2. 22.4 L

3. 11.2 L

4. 5.6 L

nomenclature ,iupac , common names..nhi aa raha

so u plz proceed a video of that wid more examples

how to determine Ecell when an electrode rxn is given?

through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and

anode) at STP (1 atm and 273 K) is :

_{4 (aq) }solution was electrolyzed using inert electrodes by passing current till the pH of the resulting solution was 2. The solution after electrolysis was neutralized and then treated with excess KI and formed I_{2}was then titrated with 0.05M Na_{2}S_{2}O_{3}. Then the required volume (in mL) of Na_{2}S_{2}O_{3}Ans: 90mL

(i) At 300 k a certain mass of a gas occupies 1 x 10

^{-4}dm^{3}volume. calculate its volume at 450 k and at the same pressure.

(ii) Convert 96

^{o}F to C^{o}41. The molar ionic conductances at infinite dilution of Mg

^{2+}and Cl^{-}are 106.1 and 76.3 ohm^{-1}cm^{2}mol^{-1}. respectively. The molar conductance of solution of MgCl_{}_{2}at infinte dilution is$\mathrm{a})29.8{\mathrm{ohm}}^{-1}{\mathrm{cm}}^{2}{\mathrm{mol}}^{-1}\phantom{\rule{0ex}{0ex}}\mathrm{b})183.4{\mathrm{ohm}}^{-1}{\mathrm{cm}}^{2}{\mathrm{mol}}^{-1}\phantom{\rule{0ex}{0ex}}\mathrm{c})285.7{\mathrm{ohm}}^{-1}{\mathrm{cm}}^{2}{\mathrm{mol}}^{-1}\phantom{\rule{0ex}{0ex}}\mathrm{d})258.7{\mathrm{ohm}}^{-1}{\mathrm{cm}}^{2}{\mathrm{mol}}^{-1}$

The charge needed to liberate 0.5 gm atomic weight of a divalent element isfaraday"s 1st low

$\mathrm{The}\mathrm{charge}\mathrm{required}\mathrm{for}\mathrm{the}\mathrm{reduction}\mathrm{of}1\mathrm{mol}\mathrm{of}{\mathrm{Cr}}_{2}{{\mathrm{O}}_{7}}^{2-}\mathrm{to}{\mathrm{Cr}}^{3+}\mathrm{is}\phantom{\rule{0ex}{0ex}}\mathrm{a})96500\mathrm{C}\phantom{\rule{0ex}{0ex}}\mathrm{b})1.93\times {10}^{5}\mathrm{C}\phantom{\rule{0ex}{0ex}}\mathrm{c})5.79\times {10}^{5}\mathrm{C}\phantom{\rule{0ex}{0ex}}\mathrm{d})2.895\times {10}^{5}\mathrm{C}$

2H

^{+}+^{}e ----->H_{2}Mg

^{2+}+ e ----> Mgwrite the balanced equation for the cell reaction . calculate E

^{0}_{cell}, E_{cell}and delta G^{0}if concentrartion are 1meach and P_{H2}= atm .