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for a particular reaction, the system absorbs 6kJ of heat and does 1.5 kJ of work on its surroundings. Calculate change in internal energy and enthalpy of system.
1) Calculate the work done in kilo joules when 2 mole of an ideal gas expand isothermally from 10 dm3 to 60 dm3 against constant pressure of one atmosphere at 298 K
Solution w = -p(v2-v1)
= -1.013× 10-5× 5 ×10-3
How to solve proceed solution
define a)racemic mixture b)enatiomers
Exothermicty favours spontanity but does not assure it? please explain it
state 2nd law of thermodynamics in term of entropy and express it mathematically.. plzz provide ans and one more question mam till now u didn't set up d software for textbook soln so culd u plzz give m the fixed date of it ...as in cbse u were providing and I was getng much knowledge then this maharastra board
How to convert L atm to joules and then joules into calories.tell me relation
what does ln means?
give me tricks to solve long numerical faster
e.g. 2.303 × 0.5 × 8.314× 300 × 0.3010
relation b/w h and u for a chemical reaction
what are the basic knowledge we must know before studying this lesson??
W max = -2.303 ×2×8.314×log 2 how to solve this equation ,how to take log2
types of processes of thermodynamics are not given in study material?
In my textbook, 4.4*10-2kg of certain matter is converted into 1 mol as following
n=[4.4*10-2(kg)] total divided by [44*10-3(kg mol-1)]=1 mol
i.e.[4.4*10-2(kg)] / [44*10-3(kg mol-1)]=1 mol
But how did they do that? pls explain as soon as.
why isothermal process is thermaly isolated?
Exothermicity favours spontanity but does not assure it
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