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Syllabus

Q.6. Two photons each ofenergy 2.5 eV are incident simultaneously on metal surface. If the work function of metal is 4.5 eV then from the surface of the metal

a) two electrons will be emitted

b) one electron will be emitted with kinetic energy equal to 0.5 eV

c) not even single electron will be emitted

d) more than two electrons will be emitted

4. Relation between stopping potential V

_{o}of a metal and the maximum velocity V of photoelectrons is.Q.11. Light of wavelength 300 nm is incident on a photosensitive surface. The stopping potential for emitted photoelectrons is 2.5 v. The wavelength of incident light is reduced to 150 nm. The stopping potential of emitted photoelectron is

Q.12. The work function of a metal is 1.5 eV. Light of wavelength 6600 A$\xb0$ is made incident on it. The maximum kinetic energy of emitted photoelectrons will be

Q.6. The work function of caesium is 2.14 eV. Find (a) the threshold frequency for caesium and (b) the wavelength of the incident light if photocurrent is brought to zero by stopping potential of 0.60 V.

(Ans : 5.164 $\times {10}^{14}$ Hz, 4537 $\stackrel{O}{A}$)

_{1}to w_{2}(w_{2}> w_{1}). If the currents before and after change ar I_{1}and I_{2}all other conditions being unchanged then.a) I

_{1}=I_{2}b) I_{1}< I_{2}c) I_{1}>I_{2}d) Noneacross the phototube.Find the work function of emmited surface.

13. A photon ofenergy hv is absorbed by a free electron of metal having work function $\mathrm{\varphi}<$hv then

a) the electron is sure to come out

b) the electron is sure to come out with K.E. (hv - $\mathrm{\varphi}$)

c) either the electron does not come out or it comes out with K.E. (hv + $\mathrm{\varphi}$)