Mathematics Solutions Solutions for Class 6 Math Chapter 12 Percentage are provided here with simple step-by-step explanations. These solutions for Percentage are extremely popular among class 6 students for Math Percentage Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Solutions Book of class 6 Math Chapter 12 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Solutions Solutions. All Mathematics Solutions Solutions for class 6 Math are prepared by experts and are 100% accurate.

Page No 64:

Question 1:

   Solve the following.
 Shabana scored 736 marks out of 800 in her exams. What was the percentage she scored?

Answer:


Marks obtained by Shabana = 736
Total marks = 800
Suppose the marks obtained by Shabana be x%. Let us write in two forms, the ratio of the number of marks obtained to the total marks, obtain an equation and solve it. Then, we have
x100=736800
x100×100=736800×100
x = 92
∴ Shabana scored 92% marks in her exams.

Page No 64:

Question 2:

Solve the following
There are 500 students in the school in Dahihanda village. If 350 of them can swim, what percent of them can swim and what percent cannot?

Answer:


Total number of students in the school = 500
Number of students who can swim = 350
Suppose the students who can swim be x%. Let us write in two forms, the ratio of the number of students who can swim to the total number of students in the school, obtain an equation and solve it. Then, we have
x100=350500
x100×100=350500×100
x = 70
∴ Percentage of students who can swim is 70%.
Now, percentage of students who can not swim = (100 − 70)% = 30%

Page No 64:

Question 3:

Solve the following
If Prakash sowed jowar on 75% of the 19500 sq m of his land, on how many sq m did he actually plant jowar?

Answer:


Suppose Prakash planted jowar in x sq m of his land. Let us write in two forms, the ratio of area of land in which jowar is planted to the total area of the land, obtain an equation and solve it. Then, we have
x19500=75100
x19500×19500=75100×19500
x = 14625
∴ Prakash planted jowar in 14625 sq m of his land.

Page No 64:

Question 4:

Solve the following
Soham received 40 messages on his birthday. Of these, 90% were birthday greetings. How many other messages did he get besides the greetings?

Answer:


Total number of messages received by Soham on his birthday = 40
Percentage of birthday greeting messages = 90%
So, percentage of other messages besides the greetings = (100 − 90)% = 10%
Suppose the number of other messages besides the greetings be x. Let us write in two forms, the ratio of the number of other messages besides greetings to the total number of messages received on birthday, obtain an equation and solve it. Then, we have
x40=10100
x40×40=10100×40
x = 4
∴ Soham received 4 other messages besides the greetings on his birthday.

Page No 64:

Question 5:

Solve the following
Of the 5675 people in a village 5448 are literate. What is the percentage of literacy in the village?

Answer:


Total number of people in a village = 5675
Number of literate people in a village = 5448
Suppose percentage of literacy in the village is x%. Let us write in two forms, the ratio of the number of literate people to the total number of people in the village, obtain an equation and solve it. Then, we have
x100=54485675
x100×100=54485675×100
x = 96
∴ Percentage of literacy in the village is 96%.

Page No 64:

Question 6:

Solve the following
In the elections, 1080 of the 1200 women in Jambhulgaon cast their vote, while 1360 of the 1700 in Wadgaon cast theirs. In which village did a greater proportion of women cast their votes?

Answer:


Total number of women in Jambhulgaon = 1200
Number of women in Jambhulgaon who cast their vote = 1080
Total number of women in Wadgaon = 1700
Number of women in Wadgaon who cast their vote = 1360
Suppose x% women cast their votes in Jambhulgaon and y% women cast their votes in â€‹Wadgaon.
Let us find the ratio of number of women who cast their vote to the total number of women in each case. We then write those ratios in two forms, obtain equations and solve them. Then, we have
x100=10801200 and y100=13601700
x100×100=10801200×100 and y100×100=13601700×100
x = 90 and y = 80
∴ 90% women cast their votes in Jambhulgaon and 80% women cast their votes in Wadgaon.
∴ A greater proportion of women cast their votes in Jambhulgaon.



View NCERT Solutions for all chapters of Class 6