Thermodynamics and Thermochemistry

Match the thermodynamic processes given under Column I with the expressions given under Column II.

Column I |
Column II |
||

(A) | Freezing of water at 273 K and 1 atm | (P) | q = 0 |

(B) | Expansion of 1 mol of an ideal gas into a vacuum under isolated conditions | (Q) | w = 0 |

(C) | Mixing of equal volumes of two ideal gases at constant temperature and pressure in an isolated container |
(R) | ΔSsys < 0 |

(D) | Reversible heating of H2(g) at 1 atm from 300 K to 600 K, followed by reversible cooling to 300 K at 1 atm |
(S) | ΔU = 0 |

(T) | ΔG = 0 |

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JEE Advanced 2015

Match the transformations in Column I with appropriate options in Column II

Column I |
Column II |
||

(A) |
(p) |
Phase transition | |

(B) |
(q) |
Allotropic change | |

(C) |
$\mathbf{2}{\mathit{H}}^{\mathbf{\bullet}}\mathbf{}\mathbf{\to}\mathbf{}{\mathit{H}}_{\mathbf{2}\mathbf{}}\mathbf{\left(}\mathit{g}\mathbf{\right)}\mathbf{}$ | (r) |
is positive |

(D) |
(s) |
is positive | |

(t) |
is negative |

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JEE Advanced 2011

(a) For He molecule, the Cv value is 3/2 R, independent of temperature. But for H

(b) Consider the three solvents of identical molar masses. Match their boiling points with their K

_{2 },the C_{V}value at very low temperature is 3/2 R, at moderate temperature it is 5/2 R and at higher temperature it is greater than 5/2 R. Explain and justify the temperature dependence.(b) Consider the three solvents of identical molar masses. Match their boiling points with their K

_{b}values:Solvent | Boiling point | K_{b} value |

X | 100°C | 0.92 |

Y | 27°C | 0.63 |

Z | 283°C | 0.53 |

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JEE 2003