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Syllabus

a) 2.8 A

b) 4.0 A

c) 5.6 A

d) 8.0 A

The answer given is 5.6 A .. explain how ?

a) 11

b) 44

c) 20

d) 22

(A) B to A and D to C

(B) A to B and C to D

(C) A to B and D to C

(D) B to A and C to D

A simple pendulum with bob of mass m and conducting wire of length L swings under gravity through an angle $2\theta $. The earth's magnetic field component in the direction perpendicular to swing is B. The maximum potential difference induced across the pendulum is

$\left(1\right)2BL\mathrm{sin}\left(\frac{\theta}{2}\right).\sqrt{gL}\left(2\right)BL\mathrm{sin}\left(\frac{\theta}{2}\right)\sqrt{gL}\phantom{\rule{0ex}{0ex}}\left(3\right)BL\mathrm{sin}\left(\frac{\theta}{2}\right).(gL{)}^{3/2}(4)BL\mathrm{sin}\left(\frac{\theta}{2}\right).(gL{)}^{2}\phantom{\rule{0ex}{0ex}}$