Call me

Have a Query? We will call you right away.

+91

E.g: 9876543210, 01112345678

We will give you a call shortly, Thank You

Office hours: 9:00 am to 9:00 pm IST (7 days a week)

What are you looking for?

Syllabus

a) Bil

^{2}b) Bil

^{2}cosac) Bil

^{2}sinad) Zero

Please tell how to take angle in these kind of questions

1. $5\left[\hat{i}+\sqrt{3}\hat{j}\right]$

2. $5\left[\sqrt{3}\hat{i}+\hat{j}\right]$

3. $5\left[\sqrt{3}i-\hat{j}\right]$

4. $5\left[\hat{i}+\hat{j}\right]$

Q.11. For the arrangement shown in figure, the magnetic induction at the centre C

(1) $\frac{3{\mu}_{0}I}{16R}$

(2) $\frac{{\mu}_{0}I}{16R}$

(3) $\frac{5{\mu}_{0}I}{16R}$

(4) $\frac{16{\mu}_{0}I}{5R}$

Q.2. A square loop of side a carries a current I. A uniform magnetic field B is along the z-axis. This loop is placed in magnetic field in four different manners as shown in figures.

a.

b.

c.

d.

Which manner corresponds to stable equilibrium?

(1) a

(2) b

(3) c

(4) d

(1) $-\sqrt{2}\hat{i}+\sqrt{2}\hat{j}$ (2) $\left(-\hat{i}-\hat{j}\right)$

(3) $-\frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j}$ (4) $-\frac{1}{\sqrt{2}}\hat{i}-\frac{1}{\sqrt{2}}\hat{j}$

a 0

b m0/2a *i1-i2

c m0/2a *i1+i2

d m0/a *i1-i2

will the jee adv marks be added with mains mark while preparing rank list??a 2 pi*10^-3T

b 2pi*10^-5T

c 4pi*10^-2 gauss

d 2pi*10^-5 gauss

_{experiment of displacement current plz explain ??}2. At the surface of a charged conductor, electrostatic field must be normal to the surface at every pointIf

Ewere not normal to the surface, it would have some non-zero component along the surface. Free charges on the surface of the conductor would then experience force and move. In the static situation, therefore,Eshould have no tangential component. Thus electrostatic field at the surface of a charged conductor must be normal to the surface at every point. (For a conductor without any surface charge density, field is zero even at the surface.) See result 5.a 35/4 mu0

b mu0/8

c 7/80 mu0

5/4 mu0

PLEASE SEE AND CHECK WHETHER IT IS crrct or not also i think the formula to be used is alos inccrct

$\mathit{Q}\mathbf{.}Aprotonmovingwithspeedualongthepositivex-axisentersaty=0inregionofuniformmagneticfield=\overrightarrow{B}=-{B}_{0}\hat{k}.Theprotonexitsfromtheregionaftersometimewiththespeedvatco-ordinatey,then$

(1) v > u, y < 0 (2) v < u, y > 0

(3) v = u, y > 0 (4) v = u, y < 0

Q.10. A uniform magnetic field B and a uniform electric field E act in a region. If a charge particle enters in this region then the charged particle may remain undeflected in the region

(1)

(2)

(3)

(4)

Sir , please explain about Biot - Savart's law in detailplz let me know this answer sir iam tryin hard to get it but im not gettin it.