Wave Optics

In Young's double slit experiment, slit -2 is wider than the slit-1, such that of the light waves through the two slits are given as:-

Slit-1 | A_{1}=A_{ₒ} sin ωt |

Slit-2 | ${A}_{2}=3{A}_{\circ}\mathrm{sin}\left(\omega t+\frac{\mathrm{\pi}}{3}\right)$ |

If

*A*is resultant amplitude and*I*is the resultant intensity at the point where phase difference is zero, then which of the following option(s) is (are) correct?
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JEE Advanced 0