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CaC> Ca(OH)_{2}+ H_{2}O -_{2}+ C_{2}H_{2}-> C_{2}H_{4} n(C_{2}H_{4}) -> ( -CH_{2}-CH_{2}- )_{n}Determine the amount of polyethylene possibly obtainable from 64.0 kg CaCl

_{2}._{2}at STP is required to reduce 0.795 of CuO to give Cu and H_{2}O.(A) KNO3 (B) NaNO3 (C) KBr (D) NaBr

_{6}]^{4-}in the given reaction[Fe(CN)

_{6}]^{-4}.....in presence of MnO_{4}^{-}/ H^{+ }--> Fe^{3+}+ CO_{2}+ NO_{3}^{-}a) 18

b) 31

c) 61

d) 28

_{1}and Kp_{2 }for the reaction X=Y+Z and A=2B are in ratio of 9:1 . if the degree of dissociation of Xand A are equal the total pressure at equibrium in both reactions are in the ratio of?_{4}, then its equivalent mass in the reaction isP

_{4}+ OH^{-}----> PH_{3}+ H_{2}PO_{2}^{-}a) M/12

b) M/4

c) M/3

d) M

a) 800 ml

b) 200 ml

c) 10 ml

d) zero

Please tell how to approach these kind of questions

A) 1

B) 2

C) 3

D) 5

_{4 }and 0.1M Al_{2}(SO_{4})_{3}_{2}and 0.4 M H_{2}SO_{4}is ?^{1}^{8}droplets. If the surface tension at the oil-water interface is 0.03 Jm^{-2x } and the area of each droplet is 12.5 x 10^{-16}m^{2}, the energy spent in the formation of oil droplets is :A) 90 J

B) 30 J

C) 900 J

D) 10 J

Explain Molar Volume?????_{2}SO_{4}, the concentration of H^{+}in the resulting solution is :A) 0.30 mol/L

B) 0.25 mol/L

C) 0.15 mol/L

D) 0.10 mol/L

_{2}O2.5 X 5.2= __________ and according to U it's answer is 13.0 .

Could U plzz explain the reason behind this ans , as in many refernce books like sl arora , it's given

to go with less number of significant number in case of multiplication and division.

Also according to me the answer should be 13.

retained" what does this mean ?

'

_{2}SO_{4}?b) what will be the strength of N/8 KOH solution in g/l ?

^{o}C is heated to 30^{o}C at constant volume.Determine the final pressure of the gas