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Syllabus
CaC2 + H2O -> Ca(OH)2 + C2H2 -> C2H4
n(C2H4) -> ( -CH2-CH2- )n
Determine the amount of polyethylene possibly obtainable from 64.0 kg CaCl2 .
(A) KNO3 (B) NaNO3 (C) KBr (D) NaBr
[Fe(CN)6]-4 .....in presence of MnO4- / H+ --> Fe3+ + CO2 + NO3-
a) 18
b) 31
c) 61
d) 28
A) 90 J
B) 30 J
C) 900 J
D) 10 J
a) 800 ml
b) 200 ml
c) 10 ml
d) zero
Please tell how to approach these kind of questions
P4 + OH- ----> PH3 + H2PO2-
a) M/12
b) M/4
c) M/3
d) M
retained" what does this mean ?
'
A) 1
B) 2
C) 3
D) 5
(i) 10.00
(ii) 1.50 X 104
Kindly tell me which rule u've used to tell the SF's here.. in each part.. (The thing is that I'm asking this question just to know the rules used here.. so plz don't forget to mention the rules used).. :')
2.5 X 5.2= __________ and according to U it's answer is 13.0 .
Could U plzz explain the reason behind this ans , as in many refernce books like sl arora , it's given
to go with less number of significant number in case of multiplication and division.
Also according to me the answer should be 13.
b) what will be the strength of N/8 KOH solution in g/l ?
A) 0.30 mol/L
B) 0.25 mol/L
C) 0.15 mol/L
D) 0.10 mol/L
In long plz i want is fast.