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Syllabus
a) [Co(en)(NH3)2Cl2]Cl
b) [Co(PPh3)2(NH3)2Cl2]Cl
c) [Co(en)3]Cl3
d) [Co(en)2Cl2]Br
is there any method to calculate them without checking all the structures ... some sort of shortcut ?
where en is ethylenediamines
1)7 2)8 3) 9 4)6
(1) sp3d2
(2) d2sp3
(3) sp3d
(4) Cannot be predicted
(1) [NiCl4]–2
(2) [NiBr4]–2
(3) [NiCl6]–4
(4) [Ni(SCN)4]–2
1. [Ni(CN)5]–3 2. [Fe(CN6)]–4 3. [Fe(H2O)5(NO)]SO4 4. [Fe(CN)6]–3
Please explain how to solve this
a) AuCl4- (sp3)
b) [Co(oxalato)3]3- (sp3d2)
c) [RhCl(PPh3)3] (dsp2)
d) [Fe(NH3)6]2+ (d2sp3)
(2) [Co(EDTA)]– > [Co(en)3]+3
(3) [NiF4]2– > [NiCl4]2–
(4) [Co(OX)3]3– > [Co(en)2Cl2]+
a) Red complex with tetrahedral geometry
b) Complex having asymmetrical H-bonding
c) Essential for synthesis of chlorophyll in green plants
d) All of these
Kindly explain the answer.
i need it in Hindi.
(A) d2sp3 hybridisation
(B) sp3d2 hybridisation
(C) Paramagnetic
(D) Diamagnetic
(A) d2sp3 hybridisation
(B) spa? hybridisation
(C) Paramagnetic
(D) Diamagnetic