Q 27 A projectile is fired horizontally with a velocity u from the top of a hill. what should be the time, in which projectile should hit the ground so that the velocity with which projectile hits the ground makes an angle of 45◦ with the horizontal (a) 2ug (b) ug (c) u2g (d) u2g
1.Equation of motion of a body is dv/dt=-4v+8, where v is the velocity in ms-1 and t is the time in second. Initial velocity of the particle was zero. Then, (a) the initial rate of change of acceleration of the particle is 8ms-2 (b) the terminal speed is 2ms-1 (c) Both (a) and (b) are correct (d) Both (a) and (b) are wrong 2. Two particles A and B are placed in gravity free space at (0,0,0)m and (30,0,0)m respectively. Particle A is projected with a velocity (5,10,5)ms-1, while particle B is projected with a velocity (10,5,5)ms-1 simultaneously. Then,
(a) they will collide at (10,20,10)m
(b) they will collide at (10,10,10)m
(c) they will never collide
(d) they will collide at 2s
Please answer fast!!!!
Multiple Choice question
Q 27 A projectile is fired horizontally with a velocity u from the top of a hill. what should be the time, in which projectile should hit the ground so that the velocity with which projectile hits the ground makes an angle of 45◦ with the horizontal
(a) (b) (c) (d)
(A) (B) (C) (D)
8. Two force each numerically equal to 10 dynes are acting as show in the figure the resultant of these two vectors will be.
Q.7. If resultant of two vectors of equal magnitude is equal to the magnitude of either vector, then what is the angle between these vectors?
(i) a force of 50 N acting along X axis.
(ii) a force of 40 N acting at angle of 60 degree to X axis
(iii)a force of 60 N acting at angle of 330 degree with X axis
Q. What is the resultant of three coplanar forces: 300 N at 0, 400 N at 30 and 400 N at 150?
Q. A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from P to Q is ( )
(1) 1.20 m (2) 1.60 m (3) 2.00 m (4) 2.40 m
1.Equation of motion of a body is dv/dt=-4v+8, where v is the velocity in ms-1 and t is the time in second. Initial velocity of the particle was zero. Then,
(a) the initial rate of change of acceleration of the particle is 8ms-2
(b) the terminal speed is 2ms-1
(c) Both (a) and (b) are correct
(d) Both (a) and (b) are wrong
2. Two particles A and B are placed in gravity free space at (0,0,0)m and (30,0,0)m respectively. Particle A is projected with a velocity (5,10,5)ms-1, while particle B is projected with a velocity (10,5,5)ms-1 simultaneously. Then,
(a) they will collide at (10,20,10)m
(b) they will collide at (10,10,10)m
(c) they will never collide
(d) they will collide at 2s
Please answer fast!!!!
Multiple Choice question
please do not re direct anywhere and answer asap.
Q3. Show that magnitude of .