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Subject: Maths, asked on 10/8/17

In an isoceles triangle,the base angles are four times the vertical angle.Find all the angles of the triangle.

Subject: Maths, asked on 27/6/17

22. If AD, BC and CF are medians of triangle ABC, prove that 3(AB2 + BC2 + CA2) = 4(AD2​ + BE2 + CF​2).

Subject: Maths, asked on 27/6/17

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21. in the adjoining figure, D and E are midpoints of the sides BC and CA respectively of a triangle ABC, right angled at C. Prove that: 
(i) 4AD2 = 4AC​2 + BC2
(ii) 4BE2 = 4BC2 + AC2

(iii) 4(AD2 + BE2) = 5AB2 


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Subject: Maths, asked on 27/6/17



16. (b) in the figure given below, ABC is a right angle ​​triangle right angled at C. if D is the midpoint of BC, prove that AB2 = 4AD2 - 3AC2. 
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Subject: Maths, asked on 27/6/17

(c) ​in the figure given below, ABCD is a square of side 7 cm. If AE = FC = CG = HA = 3 cm,
(i) prove that EFGH is a rectangle.
(ii) find the area and perimeter of EFGH.
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Subject: Maths, asked on 26/6/17

16.(i) in figure given below, BC = ​​5 cm, angle B = 90°,AB = 5AE, CD = 2AE and AC = ED. calculate the length of EA, CD, AB and AC.

Subject: Maths, asked on 26/6/17

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15.(c) in the figure given above, angle D = 90°, AB = 16 cm, BC = 12 cm and CA = 6 cm. find CD.

Subject: Maths, asked on 20/6/17

7. ABC is a right angled triangle with angle A = 90°, AB = 6 cm and AC = 8 cm. A circle with centre O is a inscribed in the triangle. Calculate the radius of the circle.☺..

Subject: Maths, asked on 20/6/17

6. let O be any point in the interior of triangle ABC, prove that OB + OC < AB + AC. 

Subject: Maths, asked on 7/6/17

Q. No. 21 pls solve

Subject: Maths, asked on 28/5/17

Pls solve 22 and 23

Subject: Maths, asked on 23/5/17

Pls solve

Subject: Maths, asked on 8/3/17

Prove that in a right angled triangle the midpoint of its hypotenuse is equidistant from each of its vertices.

Subject: Maths, asked on 1/12/16

Please solve , Sir .

Subject: Maths, asked on 1/9/17

Please solve the 5th question.
Please do not provide any link.
Q.5. In the figure, given below, AB = AC. Prove that :∠BOC =∠ACD.

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