0.2x + 0.3y=1.3
0.4x+ 0.5y=2.3
Solve it using substitution method?
0.2x+0.3y=1.3
2x/10+3y/10=13/10
(2x+3y)/10=13/10
2x+3y=13 cancelling 10 from both sides
3y=13-2x
y=(13-2x)/3 ------(1)
equation no. 2 ----->0.4x+0.5y=23
again 4x+5y=23 ----(2)
substituting the value of y from (1) in (2)
4x+5{(13-2x)/3}=23
4x+65/3-10x/3=23
4x-10x/3=23-65/3
(12x-10x)/3=(69-65)/3
12x-10x=69-65
2x=4
x=2
now substitute the value of x in any equation to get the value of y
y=3
thus, x=2 y=3