A double convex lens (n = 1.5 )in air has its focal length equal to 10 cm. When immersed in water (n = 4/3 ) its focal length will be

1. 40/3 cm

2. 7.5 cm

3. 40 cm

4. Infinity

focal length=R/2

so i think focal length is a constant quantity ...... if we place the lens in water then its focal length doesnt change because radius of curvature is constant..

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btw...aap ye question kis book se laye hain?????
//''''

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sry for the wrong answer

according to me its focal length increasess

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Dude NTSE ki book hai.

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The focal length of a lensin aircan be calculated from thelensmaker's equation:

f ' / f = 1.5-1 / (1.5-4/3 )/ 4/3 = 0.5 x8 =4

f ' = 4x10=40 cm

Therefore the answer is 3) 40 cm

Cheers!

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The focal length of a lensin aircan be calculated from thelensmaker's equation:

f ' / f = 1.5-1 / (1.5-4/3 )/ 4/3 = 0.5 x8 =4

f ' = 4x10=40 cm

Therefore the answer is 3) 40 cm

Cheers!

  • 0
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