A father with 8 children takes 3 children at a time to zoological garden, as often he could without taking the same 3 children together more than 1,Then
- number of time each child will go to zoological garden is?
- number of times a particular child will not go to garden is?
- number of times he will go to zoological garden is?
The number of times the father would go to the zoological garden = Number of ways of selection of 3 children taken at a time = 8 C 3 = 56
Number of times a child will go to the zoological garden = Number of times he is accompanied by two other = 1 ×7 C 2 = 21
⇒ Number of times a child will not go to the zoological garden:
= 56 − 21 = 35
Number of times a child will go to the zoological garden = Number of times he is accompanied by two other = 1 ×
⇒ Number of times a child will not go to the zoological garden:
= 56 − 21 = 35