ABC is an isosceles triangle with AB=AC. P is any point on BC. Perpendiculars PQ and PR are drawn to sides AB and AC respectively. Also, CS _|_ AB. Prove that CS=PQ+PR. Share with your friends Share 0 Priyanka Kedia answered this Refer the following link : https://www.meritnation.com/ask-answer/question/1-abc-is-an-isosceles-triangle-with-ab-ac-p-is-any-point/areas-of-parallelograms-and-triangles/7350829 0 View Full Answer