calculate the wavelength of fired bullet having mass of 10g and velocity 6.626 x 10³cm/sec

According to De Broglie equation :

$$\begin{gathered} \mathrm{\lambda } = \frac{\mathrm{h}}{\mathrm{mv}} \\ \mathrm{where} \mathrm{\lambda } = \mathrm{wavelength} \\ \mathrm{h} (\mathrm{Plancks} \mathrm{constant}) = 6.626\times {10}^{34} \mathrm{kg} {\mathrm{m}}^2{\mathrm{s}}^{-1} \\ \mathrm{m} = \mathrm{mass} \mathrm{of} \mathrm{particle} \\ \mathrm{v} = \mathrm{velocity} \mathrm{of} \mathrm{particle} \end{gathered}$$

Given m = 10 g = 10 ​$\times$ 10^-3  kg
v = 6.626 $\times$ 10³ cm/s = ​6.626 $\times$ 10³  $\times$  10^-2​ m/ s = ​​6.626 $\times$ 10¹ m/ s

​Thus
 $$\begin{gathered} \mathrm{\lambda } =\frac{ 6.626 \times {10}^{34} \mathrm{kg} {\mathrm{m}}^{2 }{\mathrm{s}}^{-1}}{10\times {10}^{-3} \mathrm{kg} \times 6.626 \times {10}^{ 1} {\mathrm{ms}}^{-1}} \\ = 1\times {10}^{35} \mathrm{m} \end{gathered}$$

Wavelength of the fired bullet is 1 ​​$\times$  10³⁵ m.