can you plzz solve this question:
1-tan^2A/1+tan^2A=Cos2A
=1-tan2a/1+tan2a
=1 - (sin2a/cos2a) / 1 + sin2a/cos2a
=(cos2a-sin2a) / (cos2a+sin2a)
=cos2a-sin2a/1
=cos2a (using cos2a=cos2a-sin2a)
can you plzz solve this question:
1-tan^2A/1+tan^2A=Cos2A
=1-tan2a/1+tan2a
=1 - (sin2a/cos2a) / 1 + sin2a/cos2a
=(cos2a-sin2a) / (cos2a+sin2a)
=cos2a-sin2a/1
=cos2a (using cos2a=cos2a-sin2a)