Equation:- 3x + y - 12 = 0.
Sol 1 = ( 3 , 3 ).
Let x be 3 and y be 3 & by substituting the values in the equation we get:-
3(3) + 3 - 12 = 0.
9 + 3 - 12 = 0.
12 - 12 = 0.
0 = 0.
L.H.S = R.H.S.
It satisfies the equation.
Now,
solution 2:- 2, 12.
let x be 2 and y be 12 & by substituting the values the in equation we get:-
3(2) + 12 - 12 = 0.
6 + 12 - 12 = 0.
18 - 12 = 0.
6 = 0.
L.H.S =/= R.H.S.
Hence solution 2 doesn't satisfies the solution.
Hope it helps and have a good day..!!!!
