cotA+tanB / cotB+tanA = cotA*tanB Share with your friends Share 3 Manbar Singh answered this LHS = cot A + tan Bcot B + tan A=1tan A + tan B1tan B + tan A=1 + tan A . tan Btan A1 + tan A . tan Btan B=1 + tan A . tan Btan A × tan B1 + tan A . tan B=1tan A × tan B=cot A . tan B=RHS 13 View Full Answer Aditya Rajput answered this LHS: cotA + tanB / cotB + tanA= (cotA + 1/cotB) / (cotB + 1/cotA)= (cotAcotB + 1) / cotB / (cotAcotB + 1) / cotA= cotA / cotB= cotAtanB= RHShence proved. 4
