Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes is root of 2 and 1/3 respectively, using the following method-
k[x2-(sum of zeroes)x+product of zeroes]

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2formula = k[x2-[sum of zeroes]x + products of zeroes ]
we have been given ,sum of zeroes = root 2 and product of zeroes is 1/3
Now,K{x2-[root 2]x + 1/3]
Now, K=3
3[x2-[root 2]x + 1/3]
3x2-3[root 2]x + 1/3 multiply 3 
3x​2-3 root 2 x +1
therefore p(x) = 3x2-3root2x+1
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