Find the sum of the sides of an isosceles triangle with 2 of its equal sides as (2x+3y-8) and the - Maths - Visualising Solid Shapes

Question

Find the sum of the sides of an isosceles triangle with 2 of its
equal sides as (2x+3y-8) and the third side as (7y+9)

Manbar Singh · Accepted Answer

Let ABC be an isosceles ∆ in which AB=AC
Now, AB=AC=2x+3y-8; BC=7y+9Sum of the sides of ∆ABC=AB+AC+BC=2x+3y-8+2x+3y-8+7y+9=2x+3y-8+2x+3y-8+7y+9=2x+2x+3y+3y+7y-8-8+9=4x+13y-7

Find the sum of the sides of an isosceles triangle with 2 of its equal sides as (2x+3y-8) and the third side as (7y+9).