Find the sum of two middle most terms of AP: -4/3,-1,-2/3,.......13/3 Share with your friends Share 25 Vipin Verma answered this Here in this AP, the first term is -4/3 and last term is 13/3.The nth term of an AP is given by a+(n-1)d=Tn, Here a is first term, d is the common difference.Tn is the last term.And d = tn+1-tn, here n is natural number.So d =-1-(-43)=13So using the formula, we get⇒-43+(n-1)13=133⇒n3=183n=18, so there are 18 term in this AP.So the two middle most term are 9th and 10th term.Hence t9th=-43+(9-1)13=43and t10th=-43+(10-1)13=53Hence the sum of two middle most terms of the AP will be 43+53=93=3. 59 View Full Answer
